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3 years ago

Express your answer in scientific notation. 1.4 x 10^9 - 8.6 x 10^8

Mathematics

1 answer:

garik1379 [7]3 years ago

4 0

Answer:

-7.5 x 10^1

Step-by-step explanation:

subtract numbers and exponents and make sure that number is between 1 and 10.

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Given: ABCD is a trapezoid, m∠1=m∠2, m∠3=m∠4, AB = CD, AC ∩ BD = O <br> Prove: m∠AOD = m∠BCD

LiRa [457]

Since AB = CD the trapezoid is isosceles, which means that ∡A = ∡D

Therefore also ∡2 = ∡3 (they are half of the congruent angles)

For the properties of parallel lines (BD and AD) crossed by a transversal (BD) we have ∡3 = ∡CBD.

Now consider triangles AOD and BCD:
∡OAD (2) = ∡ADO (3) = ∡CBD (3) = ∡CDB (4)

T<span>he sum of the angles of a triangle must be 180°, t</span>herefore:
∡AOD = 180 - ∡2 - ∡3
∡BCD = 180 - ∡3 - ∡4

∡AOD = ∡BCD because their measure is the difference of congruent angles.

6 0

4 years ago

Pleaseee helppp answer correctly !!!!!!!!!!! Will mark Brianliest !!!!!!!!!!!!!!!

rewona [7]

IP and JQ i think is correct

6 0

3 years ago

I want to know how to solve this equation

andre [41]

9514 1404 393

Answer:

Step-by-step explanation:

To find the inverse of y = f(x), solve the equation x = f(y) for y. For these functions, that's about the easiest way to do it.

A. x = ∛(3y) ⇒ x³ = 3y ⇒ x³/3 = y . . . . . does not match g(x)

B. x = 11y -4 ⇒ x +4 = 11y ⇒ (x +4)/11 = y . . . . matches g(x)

C. x = 3/y -10 ⇒ x +10 = 3/y ⇒ 3/(x+10) = y . . . . does not match g(x)

D. x = y/12 +15 ⇒ x -15 = y/12 ⇒ 12(x -15) = y . . . . does not match g(x)

_____

<em>Additional comment</em>

This is repeated application of the "solve for ..." process. In general, that process "undoes" what is "done" to the variable. The order of operations can tell you the order of the things that are done. The undoing is in the reverse order.

You need to be completely comfortable with the properties of equality (addition, subtraction, multiplication, division), and you need to understand the inverse functions of the functions we usually use: (powers, roots), (exponentials, logarithms), (trig functions, inverse trig functions). Of course, the inverse of addition is subtraction; the inverse of multiplication is division.

Above, we used a "shortcut" a couple of times:

a = b/c ⇒ c = b/a . . . . . equivalent to multiplying both sides by c/a.

8 0

3 years ago

Riding a bike a person takes 20 minutes to go to work. The trip back home takes 30 minutes. If the rate back is 8 mph slower tha

Ghella [55]

<h2>Answer:</h2>

Trip to work has rate: 24 mph

Trip back to home has rate: 18 mph

Distance to work is: 480 m

<h2>Step-by-step explanation:</h2>

We know that speed is defined as the ratio of distance to time.

i.e.

$Speed=\dfrac{Distance}{Time}$

Let the distance traveled to work be: x m.

Now, while going to work it takes a person 20 minutes.

This means that the speed of the person while going to work is:

$S_1=\dfrac{x}{20}$

Also, the time taken to come back home is: 30 minutes.

This means that the speed of person while riding to home is:

$S_2=\dfrac{x}{30}$

Also, it is given that the rate back is 8 mph slower than the trip to work.

This means that:

$S_1-S_2=8$

i.e.

$\dfrac{x}{20}-\dfrac{x}{30}=8\\\\i.e.\\\\\dfrac{30x-20x}{600}=8\\\\i.e.\\\\\dfrac{10x}{600}=8\\\\i.e.\\\\\dfrac{x}{60}=8\\\\i.e.\\\\x=480\ \text{m}$

Hence, the distance to work is: 480 m.

Also, the rate while going to work is:

$=\dfrac{480}{20}\\\\=24\ \text{mph}$

and the trip back to home is covered with the speed:

$=\dfrac{480}{30}\\\\=16\ \text{mph}$

6 0

3 years ago

Going through York Canal, he drives 5 miles in 15 minutes. Later on as he crosses Stover Lake, he drives 30 minutes at the same

SVETLANKA909090 [29]

When going through York Canal, his speed is 1 mile per 3 minutes.

If going by this speed while crossing Stover Lake, he would drive 10 miles in 30 minutes.

Therefore, he drove 10 miles.

5 0

4 years ago