Answer:
The value of n is 5
Step-by-step explanation:
Here, we want to get the value of n
To get this, we will need to use the appropriate trigonometric identity
As we can see, n represents the opposite as it the side that faces the angle given
m is the hypotenuse as it is the side that faces the right angle
The last side is called the adjacent
The trigonometric identity we want to use is that which connects the opposite to the adjacent
The appropriate trigonometric identity to use in this case is the tan
Thus;
Mathematically, the tan is the ratio of the opposite to the adjacent
hence;
tan 30 = n/ 5 √3
n = 5 √3 * 1/ √3
n = 5
Answer:
We accept H₀
Step-by-step explanation:
Normal Distribution
size sample n = 69
sample mean 18.94
standard deviation 8.3
Is a one tailed-test to the left we are traying of find out is we have enough evidence to say that the mean is less than 20 min.
1.-Test hypothesis H₀ ⇒ μ₀ = 20
Alternative hypothesis Hₐ ⇒ μ₀ < 20
2.- Critical value
for α = 0.1 we find from z Table
z(c) = - 1.28
3.-We compute z(s)
z(s) = [ ( μ - μ₀ ) / (σ/√n) ⇒ z(s) = [( 18.94 - 20 )*√69)/8.3]
z(s) = ( -1.06)*8.31/8.3
z(s) = - 1.061
4.- We compare
z(c) and z(s) -1.28 > -1.061
Then z(c) > z(s)
z(s) in inside acceptance region so we accept H₀
Answer:
(1)3(x+3)
(2)5(x+3)
Step-by-step explanation:
(1) common taking
(2) common taking
Answer:
Step-by-step explanation:
Answer:
The 98% confidence interval for the mean purchases of all customers is ($37.40, $61.74).
Step-by-step explanation:
We have that to find our 
level, that is the subtraction of 1 by the confidence interval divided by 2. So:
Now, we have to find z in the Ztable as such z has a pvalue of 
.
So it is z with a pvalue of 
, so 
Now, find M as such
In which 
is the standard deviation of the population and n is the size of the sample.
The lower end of the interval is the mean subtracted by M. So it is 49.57 - 12.17 = $37.40.
The upper end of the interval is the mean added to M. So it is 49.57 + 12.17 = $61.74.
The 98% confidence interval for the mean purchases of all customers is ($37.40, $61.74).
