Answer:
Given info in numersical form:
(14+42)÷(7+4)²
= 56÷11²
= 56÷(11×11)
= 56÷121
= 0.46
This is how I find the GCF.
I find the prime factors.
63/3 = 21
21/3 = 7
7/7 = 1
81/3 = 27
27/3 = 9
9/3 = 3
3/3 = 1
Then I find the common prime factors:
63: 3 x 3 x 7
81: 3 x 3 x 3 x 3
Then I multiply the common prime factors:
3 x 3 = 9
The GCF for 63 and 81 (number 3) is 9.
I bet you can use this method for all the other GCFs! :)
For this one, find the prime factors like before, and if there aren't any besides one, then it's a prime number.
75/3 = 25
25/5 = 5
5/5 = 1
The prime factorization for 75 is 3 x 5 x 5
(I don't know the answer to 7, 8, 9, 10, 11, 12, 25, or 26, sorry!)
The graph of f(x) = x^2 has only one x-intercept since its vertex is at the origin, (0,0) and it opens up. When comparing the graph of <span>g(x) = -x^2 -5 with the graph of f(x) = x^2, g(x) is the graph of f(x) first reflected in the x-axis and then translated 5 units down. The graph of g(x) has no x-intercepts since its a parabola that opens downward (result of reflection in x-axis) and its vertex at (0,-5) is situated below the x-axis.</span>
Answer:
how rough it is as and kinda dry
A Little but not that much so im straight
