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maks197457 [2]
2 years ago
10

Q1 Write the number in expanded form for the significant digits ( as fractions)

Mathematics
1 answer:
Dimas [21]2 years ago
6 0

To write in expanded form is to simply mean writing each number into its place value.

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A polygon has the following coordinates: A(-4,-3), B(4,-3), C(4,-7), D(-4,-7). Find the length of BC.
KIM [24]

Answer:

9

Step-by-step explanation:

8 0
3 years ago
40 PIONTS!!! HELP PLZ ANSWER THE QUESTIONS (IF YOU DONT ASWER THE QUETIONS THEN I WILL REPORT YOU)
allochka39001 [22]

Answer:

quadrant 1.

Step-by-step explanation:

A:(9,3)

B:(7,5)

C:(5,2)

Hope this helped you.

4 0
2 years ago
Select the correct answer. What is the average rate of change of f(x), represented by the table of values, over the interval [-3
prisoha [69]

Answer:

<h2>                                                              . . ..................      </h2>

Step-by-step explanation:\

7 0
2 years ago
In ΔDEF, the measure of ∠F=90°, FD = 63 feet, and DE = 71 feet. Find the measure of ∠E to the nearest degree.
stepan [7]

Answer:

Step-by-step explanation:

∠F=90°, FD = 63 feet, and DE = 71 feet.

That's a right angle triangle also.

measure of ∠E to the nearest degree

sin∠E = 63/71

sin∠E = 0.8873

∠E= sin^-1 0.8873

∠E= 62.5°

7 0
3 years ago
Find the absolute extrema of f(x) = e^{x^2+2x}f ( x ) = e x 2 + 2 x on the interval [-2,2][ − 2 , 2 ] first and then use the com
fredd [130]

f(x)=e^{x^2+2x}\implies f'(x)=2(x+1)e^{x^2+2x}

f has critical points where the derivative is 0:

2(x+1)e^{x^2+2x}=0\implies x+1=0\implies x=-1

The second derivative is

f''(x)=2e^{x^2+2x}+4(x+1)^2e^{x^2+2x}=2(2x^2+4x+3)e^{x^2+2x}

and f''(-1)=\frac2e>0, which indicates a local minimum at x=-1 with a value of f(-1)=\frac1e.

At the endpoints of [-2, 2], we have f(-2)=1 and f(2)=e^8, so that f has an absolute minimum of \frac1e and an absolute maximum of e^8 on [-2, 2].

So we have

\dfrac1e\le f(x)\le e^8

\implies\displaystyle\int_{-2}^2\frac{\mathrm dx}e\le\int_{-2}^2f(x)\,\mathrm dx\le\int_{-2}^2e^8\,\mathrm dx

\implies\boxed{\displaystyle\frac4e\le\int_{-2}^2f(x)\,\mathrm dx\le4e^8}

5 0
3 years ago
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