Converting Denary to Binary

Implemente a função ao lado, que recebe um preço e um booleano indicando se já está com desconto ou não. Se o preço for maior qu

Andrew [12]

Answer:

function pecoDesconto(preco, estaComDesconto) {

let p = preco;

let desconto = estaComDesconto;

if(p > 100 && desconto == false){

return "Quero pechinchar";

}else{

return "Negócio fechado";

}

Explanation:

function pecoDesconto(preco, estaComDesconto) {

// Implemente a função ao lado, que recebe um preço//

let p = preco;

// variavel que indica desconco//

let desconto = estaComDesconto;

//Se o preço for maior que 100 e não estiver com desconto, a função deve retornar Quero pechinchar.//

if(p > 100 && desconto == false){

return "Quero pechinchar";

//Caso contrário, deve retornar Negócio fechado

}else{

return "Negócio fechado"

}

só te faltou ler com atenção, e um pouco de logica!

7 0

2 years ago

Which activity represents a violation of the licensing agreement

kvasek [131]

Could you give the answers it gives you? It should be along the lines of purposeful destruction of equipment.

5 0

3 years ago

Read 2 more answers

Using Python I need to Prompt the user to enter in a numerical score for a Math Class. The numerical score should be between 0 a

yaroslaw [1]

Answer:

The program doesn't use comments; See explanation section for detailed line by line explanation

Program starts here

def lettergrade(subject,score):

print(subject+": "+str(score))

if score >= 90 and score <= 100:

print("Letter Grade: A")

elif score >= 80 and score <= 89:

print("Letter Grade: B")

elif score >= 70 and score <= 79:

print("Letter Grade: C")

elif score >= 60 and score <= 69:

print("Letter Grade: D")

elif score >= 0 and score <= 59:

print("Letter Grade: F")

else:

print("Invalid Score")

maths = int(input("Maths Score: "))

english = int(input("English Score: "))

pe = int(input("PE Score: "))

science = int(input("Science Score: "))

arts = int(input("Arts Score: "))

lettergrade("Maths Class: ",maths)

lettergrade("English Class: ",english)

lettergrade("PE Class: ",pe)

lettergrade("Science Class: ",science)

lettergrade("Arts Class: ",arts)

Explanation:

The program makes the following assumptions:

Scores between 90–100 has letter grade A

Scores between 80–89 has letter grade B

Scores between 70–79 has letter grade C

Scores between 60–69 has letter grade D

Scores between 0–69 has letter grade E

Line by Line explanation

This line defines the lettergrade functions; with two parameters (One for subject or class and the other for the score)

def lettergrade(subject,score):

This line prints the the score obtained by the student in a class (e.g. Maths Class)

print(subject+": "+str(score))

The italicized determines the letter grade using if conditional statement

This checks if score is between 90 and 100 (inclusive); if yes, letter grade A is printed

if score >= 90 and score <= 100:

print("Letter Grade: A")

This checks if score is between 80 and 89 (inclusive); if yes, letter grade B is printed

elif score >= 80 and score <= 89:

print("Letter Grade: B")

This checks if score is between 70 and 79 (inclusive); if yes, letter grade C is printed

elif score >= 70 and score <= 79:

print("Letter Grade: C")

This checks if score is between 60 and 69 (inclusive); if yes, letter grade D is printed

elif score >= 60 and score <= 69:

print("Letter Grade: D")

This checks if score is between 0 and 59 (inclusive); if yes, letter grade F is printed

elif score >= 0 and score <= 59:

print("Letter Grade: F")

If input score is less than 0 or greater than 100, "Invalid Score" is printed

else:

print("Invalid Score")

This line prompts the user for score in Maths class

maths = int(input("Maths Score: "))

This line prompts the user for score in English class

english = int(input("English Score: "))

This line prompts the user for score in PE class

pe = int(input("PE Score: "))

This line prompts the user for score in Science class

science = int(input("Science Score: "))

This line prompts the user for score in Arts class

arts = int(input("Arts Score: "))

The next five statements is used to call the letter grade function for each class

lettergrade("Maths Class: ",maths)

lettergrade("English Class: ",english)

lettergrade("PE Class: ",pe)

lettergrade("Science Class: ",science)

lettergrade("Arts Class: ",arts)

7 0

3 years ago

HELLLP

mojhsa [17]

Explanation:

The output of this program is 5 7, because the first time bruce is printed, his value is 5, and the second time, his value is 7. The comma at the end of the first print statement suppresses the newline after the output, which is why both outputs appear on the same line.

Here is what multiple assignment looks like in a state diagram:

With multiple assignment it is especially important to distinguish between an assignment operation and a statement of equality. Because Python uses the equal sign (=) for assignment, it is tempting to interpret a statement like a = b as a statement of equality. It is not!

First, equality is symmetric and assignment is not. For example, in mathematics, if a = 7 then 7 = a. But in Python, the statement a = 7 is legal and 7 = a is not.

Furthermore, in mathematics, a statement of equality is always true. If a = b now, then a will always equal b. In Python, an assignment statement can make two variables equal, but they don’t have to stay that way:

a = 5

4 0

3 years ago

Read 2 more answers

The Beaufort Wind Scale is used to characterize the strength of winds. The scale uses integer values and goes from a force of 0,

TEA [102]

Answer:

ranforce = randi([0, 12]);

if (ranforce == 0)

disp('There is no wind')

else if(ranforce>0 && ranforce <7)

disp('There is a breeze')

else if(ranforce>6 && ranforce <10)

disp('This is a gale')

else if(ranforce>9 && ranforce <12)

disp('It is a storm')

else if(ranforce==12)

disp('Hello, Hurricane!')

end

Explanation:

Replace all switch case statements with if and else if statements.

An instance is:

case {7,8,9}

is replaced with

else if(ranforce>9 && ranforce <12)

All other disp statements remain unchanged

5 0

3 years ago