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3 years ago

Beatrice withdrew 28 dollars from her checking account. What is the integer?

Mathematics

2 answers:

Bingel [31]3 years ago

8 0

An integer is a whole number so 28 is the answer

garik1379 [7]3 years ago

7 0

Integer of what? 28? if so, the integer of a number is its opposite below zero. if you want the integer of 28 your answer is negative 28, or -28.

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2. In the figure given alongside, find the values of x and y.

dimulka [17.4K]

Answer:

y=50°

x=232°

Step-by-step explanation:

cuz y+130=180

y=50

and

y+68+x=360°

50+68+x=360°

so x =232

5 0

2 years ago

The perimeter of a rectangular deck measured 130 m. What are the possible

fomenos

Answer:

The possible dimensions of the deck can be anything that adds up to be 130 m.

Step-by-step explanation:

The perimeter could be 1m x 64m.

Two sides would be 1m each (so 2m total) and the other two sides would be 64m each (128m total). 2 + 128 = 130m.

The perimeter could be 15m x 50m.

Two sides would be 15m each (so 30m total) and the other two sides would be 50m each (100m total). 30 + 100 = 130m.

8 0

3 years ago

What is the sum 5/3 +(1/5) please and explain

solmaris [256]

We need to find a common denominator(bottom number of fraction)

5/3 = 25/15 (multiply both top and bottom by 5)
1/5 = 3/15 (multiply both top and bottom by 3)

Now since the denominator is the same we can add to get 25/15 + 3/15 = 28/15

7 0

3 years ago

Read 2 more answers

Use triangle ABC drawn below & only the sides labeled. Find the side of length AB in terms of side a, side b & angle C o

Brrunno [24]

Answer:

$AB = \sqrt{a^2 + b^2-2abCos\ C}$

Step-by-step explanation:

Given:

The above triangle

Required

Solve for AB in terms of a, b and angle C

Considering right angled triangle BOC where O is the point between b-x and x

From BOC, we have that:

$Sin\ C = \frac{h}{a}$

Make h the subject:

$h = aSin\ C$

Also, in BOC (Using Pythagoras)

$a^2 = h^2 + x^2$

Make $x^2$ the subject

$x^2 = a^2 - h^2$

Substitute $aSin\ C$ for h

$x^2 = a^2 - h^2$ becomes

$x^2 = a^2 - (aSin\ C)^2$

$x^2 = a^2 - a^2Sin^2\ C$

Factorize

$x^2 = a^2 (1 - Sin^2\ C)$

In trigonometry:

$Cos^2C = 1-Sin^2C$

So, we have that:

$x^2 = a^2 Cos^2\ C$

Take square roots of both sides

$x= aCos\ C$

In triangle BOA, applying Pythagoras theorem, we have that:

$AB^2 = h^2 + (b-x)^2$

Open bracket

$AB^2 = h^2 + b^2-2bx+x^2$

Substitute $x= aCos\ C$ and $h = aSin\ C$ in $AB^2 = h^2 + b^2-2bx+x^2$

$AB^2 = h^2 + b^2-2bx+x^2$

$AB^2 = (aSin\ C)^2 + b^2-2b(aCos\ C)+(aCos\ C)^2$

Open Bracket

$AB^2 = a^2Sin^2\ C + b^2-2abCos\ C+a^2Cos^2\ C$

Reorder

$AB^2 = a^2Sin^2\ C +a^2Cos^2\ C + b^2-2abCos\ C$

Factorize:

$AB^2 = a^2(Sin^2\ C +Cos^2\ C) + b^2-2abCos\ C$

In trigonometry:

$Sin^2C + Cos^2 = 1$

So, we have that:

$AB^2 = a^2 * 1 + b^2-2abCos\ C$

$AB^2 = a^2 + b^2-2abCos\ C$

Take square roots of both sides

$AB = \sqrt{a^2 + b^2-2abCos\ C}$

6 0

3 years ago

Solve 8x+6=5(x+1)+2 please help me with this

NNADVOKAT [17]

Solution: x=1/3
decimal: x=0.3333...

8 0

3 years ago

Read 2 more answers