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3 years ago

Pls help am failing Hehehehgshdhdjsjbsvdv

Mathematics

1 answer:

ludmilkaskok [199]3 years ago

7 0

Answer:

should be B

Step-by-step explanation:

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Find exact values for sin θ and tan θ if cos θ = -4/9 and tan θ > 0.

julsineya [31]

Answer:

Part 1) $sin(\theta)=-\frac{\sqrt{65}}{9}$

Part 2) $tan(\theta)=\frac{\sqrt{65}}{4}$

Step-by-step explanation:

we have that

The cosine of angle theta is negative and the tangent of angle theta is positive

That means that the sine of angle theta is negative

step 1

Find $sin(\theta)$

we know that

$sin^{2}(\theta) +cos^{2}(\theta)=1$

we have

$cos(\theta)=-\frac{4}{9}$

substitute

$sin^{2}(\theta) +(-\frac{4}{9})^{2}=1$

$sin^{2}(\theta) +\frac{16}{81}=1$

$sin^{2}(\theta)=1-\frac{16}{81}$

$sin^{2}(\theta)=\frac{65}{81}$

square root both sides

$sin(\theta)=\pm\frac{\sqrt{65}}{9}$

Remember that

In this problem the sine of angle theta is negative

$sin(\theta)=-\frac{\sqrt{65}}{9}$

step 2

Find $tan(\theta)$

we know that

$tan(\theta)=\frac{sin(\theta)}{cos(\theta)}$

we have

$sin(\theta)=-\frac{\sqrt{65}}{9}$

$cos(\theta)=-\frac{4}{9}$

substitute the given values

$tan(\theta)=-\frac{\sqrt{65}}{9}:-\frac{4}{9}=\frac{\sqrt{65}}{4}$

3 0

3 years ago

zoe wrote 3/5 of her essay in 30 minutes. assuming she wrote the paper at a constant rate the entire time, which expression can

vodomira [7]

3/5 in 30 mins, 5*30=150, then she would write 3/150 or 1/50 each minute

6 0

3 years ago

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How to do: 4(x+7)=2(x+7)

andre [41]

4(x+7) becomes 4x+28 you multipli the 4 in parentheses ans 2(x+7) becomes 2x+14

4x+28=2x+14 you move the x termes to the left and other numbers to the right look:

4x-2x=14-28 when you change the sides always change the sign +or-
2x=-14
2x/2=-14/2
X=-7

3 0

3 years ago

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Y=x+ 5 <br>y = 6<br>HELP!!<br>Solve this system of equation algerbraically.

kati45 [8]

Answer:

x = 1

Step-by-step explanation:

plug y = 6 on to the equation y =x + 5

=> 6 = x +5

=> x = 1

5 0

3 years ago

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Nina is bouncing on a trampoline her fourth bounce is 6ft high each bounce afterwards is two thirds as high as the bounce before

V125BC [204]

Answer:

8/3ft

Step-by-step explanation:

To find how high she would bounce, we need to first understand that her height of each jump would be multiplied by 2/3 given that each bounce afterwards is two thirds as high as the bounce before.

We can then set the equation:

6 x 2/3 x 2/3

=6 x (2/3)^2

=8/3

Therefore the answer is 8/3 ft.

Hope it helps!

8 0

3 years ago