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2 years ago

Help me with math plz ASAP please

Mathematics

2 answers:

Marina86 [1]2 years ago

5 0

(-3)(7) = -21.

y^8 and c^3 have different bases (y and c) and thus cannot be merged.

So we end up with -21c^3y^8.

Sidana [21]2 years ago

5 0

Answer:

$\large\boxed{-21c^3y^8}$

Step-by-step explanation:

$-3y^8\cdot7c^3=(-3\cdot7)(y^8c^3)=-21c^3y^8$

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A scuba diver is at an elevation of −18 ft. She then descends 30 ft deeper. What is the scuba diver's new elevation?

sladkih [1.3K]

-18 - 30 = -48
The Scuba Diver is now 48 feet below sea level.

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2 years ago

A square has a side length of 2.5 feet if the square is dilated by a factor of 2.5 what is the length of a side of the new squar

Anni [7]

Answer:

6.25

Step-by-step explanation:

You would multiply 2.5 by itself since you're dilating your side length.

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2 years ago

Please help me solve 3x + 4y =15 and 3x - y = 30 it is for Algebra I

Makovka662 [10]

Answer:

Step-by-step explanation:

Given the simultaneous equation

3x+4y=15. Equation 1

3x-y=30. Equation 2

Using elimination method

Sutract equation 2 from 1

Then, will have

3x-3x+4y--y=15-50. -×-=+

4y+y=-15

5y=-15

Divide Both sides by 5

y=-15/5

y=-3

From equation 2

3x-y=30

3x--3=30

3x+3=30

3x=30-3

3x=27

Divide both side by 3

x=27/3

x=9

Then, x=9 and y=-3

7 0

2 years ago

Read 2 more answers

Farmer has to transport a fox, a chicken, and a sack of corn across a river. she can carry only one item at a time. if left toge

vagabundo [1.1K]

Step by step guide
1)carry the chicken over and put it there
2) farmer cross alone to carry the corn over and carry the chicken back
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6 0

2 years ago

GCSE 995381

nikdorinn [45]

Answer:

$2.9 cm^2$

Step-by-step explanation:

Given,

Angle of sector = 30°

Radius of circle, r = 8 cm

Area of the shaded region, A =?

The diagram is attached below.

Now,

Area of shaded region = Area of sector - Area of triangle

Area of triangle = $\frac{1}{2}\times base \times height$

We know that,

$\sin \theta = \dfrac{P}{H}$

$\sin 30^\circ= \dfrac{P}{8}$

$P = \dfrac{8}{2}$

$P = 4\ cm$

And

$\cos \theta =\dfrac{B}{H}$

$\cos 30^\circ = \dfrac{B}{8}$

$B = \dfrac{8\times \sqrt{3}}{2}$

$B = 4\sqrt 3$

Area of sector = $\dfrac{\theta}{360^\circ}\times \pi r^2$

Area of sector = $\dfrac{30^\circ}{360^\circ}\times \pi \times 8^2$

= 16.75 cm^2

Area of triangle = $\dfrac{1}{2} \times 4\sqrt 3 \times 4$

= 13.85 cm^2

Area of shaded region = 16.75 - 13.85

= $2.9 cm^2$

7 0

2 years ago