Step-by-step explanation:
no it doesn't equal
!
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Answer:
14) The equation of the tangent line to the curve
at x = -1 is
15) The rate of learning at the end of eight hours of instruction is 
Step-by-step explanation:
14) To find the equation of a tangent line to a curve at an indicated point you must:
1. Find the first derivative of f(x)

2. Plug x value of the indicated point, x = -1, into f '(x) to find the slope at x.

3. Plug x value into f(x) to find the y coordinate of the tangent point

4. Combine the slope from step 2 and point from step 3 using the point-slope formula to find the equation for the tangent line

5. Graph your function and the equation of the tangent line to check the results.
15) To find the rate of learning at the end of eight hours of instruction you must:
1. Find the first derivative of f(x)
![w(t)=15\sqrt[3]{t^2} \\\\\frac{d}{dt}w= \frac{d}{dt}(15\sqrt[3]{t^2})\\\\w'(t)=15\frac{d}{dt}\left(\sqrt[3]{t^2}\right)\\\\\mathrm{Apply\:the\:chain\:rule}:\quad \frac{df\left(u\right)}{dx}=\frac{df}{du}\cdot \frac{du}{dx}\\\\f=\sqrt[3]{u},\:\:u=\left(t^2\right)\\\\w'(t)=15\frac{d}{du}\left(\sqrt[3]{u}\right)\frac{d}{dt}\left(t^2\right)\\\\w'(t)=15\cdot \frac{1}{3u^{\frac{2}{3}}}\cdot \:2t\\\\\mathrm{Substitute\:back}\:u=\left(t^2\right)](https://tex.z-dn.net/?f=w%28t%29%3D15%5Csqrt%5B3%5D%7Bt%5E2%7D%20%5C%5C%5C%5C%5Cfrac%7Bd%7D%7Bdt%7Dw%3D%20%5Cfrac%7Bd%7D%7Bdt%7D%2815%5Csqrt%5B3%5D%7Bt%5E2%7D%29%5C%5C%5C%5Cw%27%28t%29%3D15%5Cfrac%7Bd%7D%7Bdt%7D%5Cleft%28%5Csqrt%5B3%5D%7Bt%5E2%7D%5Cright%29%5C%5C%5C%5C%5Cmathrm%7BApply%5C%3Athe%5C%3Achain%5C%3Arule%7D%3A%5Cquad%20%5Cfrac%7Bdf%5Cleft%28u%5Cright%29%7D%7Bdx%7D%3D%5Cfrac%7Bdf%7D%7Bdu%7D%5Ccdot%20%5Cfrac%7Bdu%7D%7Bdx%7D%5C%5C%5C%5Cf%3D%5Csqrt%5B3%5D%7Bu%7D%2C%5C%3A%5C%3Au%3D%5Cleft%28t%5E2%5Cright%29%5C%5C%5C%5Cw%27%28t%29%3D15%5Cfrac%7Bd%7D%7Bdu%7D%5Cleft%28%5Csqrt%5B3%5D%7Bu%7D%5Cright%29%5Cfrac%7Bd%7D%7Bdt%7D%5Cleft%28t%5E2%5Cright%29%5C%5C%5C%5Cw%27%28t%29%3D15%5Ccdot%20%5Cfrac%7B1%7D%7B3u%5E%7B%5Cfrac%7B2%7D%7B3%7D%7D%7D%5Ccdot%20%5C%3A2t%5C%5C%5C%5C%5Cmathrm%7BSubstitute%5C%3Aback%7D%5C%3Au%3D%5Cleft%28t%5E2%5Cright%29)

2. Evaluate the derivative a t = 8

The rate of learning at the end of eight hours of instruction is 
Answer:
110in
Step-by-step explanation:
↪Areas related to trapeziods..Basically the Area of a trapezium is given by Area = 1/2 ( sum of the non -parallel sides ) × H ↪thus we get as ..Area = 1/2 ( 9 + 13) 10 =》 1/2 ( 22 ) 10 = 110 ↪thus the area is 110 in^2_________________________
(2/3) x -6= 18
2x/3 = 18+6
2x/3 = 24
2x = 24•3
X= 24•3/2
X= 12•3
X= 36