Sequence 1,5,9,13,...
A(0) = 1 +4x0=1
A(1) =1 + 4x1 = 5
A(2) = 1+ 4x2= 9
A(3) = 1 +4x3=13
A(n)= 1+4n A(n-1) = 1+4(n-1) =1+4n-4= - 3+4n
A(n) - A(n-1) = (1+4n) - (-3=4n) = 4
A(n) = A(n-1) +4; 29 is the answer
The answer would be B and D. This can be found by putting the x and y values into the inequality to find whether or not they are true.
Answer: b. 134
Step-by-step explanation:
Given : A minimum usual value of 135.8 and a maximum usual value of 155.9.
Let x denotes a usual value.
i.e. 135.8< x < 155.9
Therefore , the interval for the usual values is [135.8, 155.9] .
If interval for any usual value is [135.8, 155.9] , then any value should lie in this otherwise we call it unusual.
Let's check all options
a. 137 ,
since 135.8< 137 < 155.9
So , it is usual.
b. 134
since 134<135.8 (Minimum value)
So , it is unusual.
c. 146
since 135.8< 146 < 155.9
So , it is usual.
d. 155
since 135.8< 1155 < 155.9
So , it is usual.
Hence, the correct answer is b. 134 .
m = −3/4 is the correct answer. Hope this helps!
