n, n + 2, n + 4 - three consecutive even integers
the twice the sum of the second and third: 2[(n + 2) + (n + 4)]
twelve less than six times the first: 6n - 12
The equation:
2[(n + 2) + (n + 4)] = 6n - 12
2(n + 2 + n + 4) = 6n - 12
2(2n + 6) = 6n - 12 <em>use distributive property</em>
(2)(2n) + (2)(6) = 6n - 12
4n + 12 = 6n - 12 <em>subtract 12 from both sides</em>
4n = 6n - 24 <em>subtract 6n from both sides</em>
-2n = -24 <em>divide both sides by (-2)</em>
n = 12
n + 2 = 12 + 2 = 14
n + 4 = 12 + 4 = 16
<h3>Answer: 12, 14, 16</h3>
Answer:
14 flats
5 plants
Step-by-step explanation:
First you would do 89/6 but since that doesn’t divide nicely you can do 90/6 to get 15 then subtract 1 since the original number was 89 and you would get 14
The 14 times 6 would get you 84
Then subtract 84 from 89 and you get 5 plants left over ^^
Answer:
rise over run
Step-by-step explanation:
how much it goes up over how far it goes to the side
Answer:
r>5
Step-by-step explanation:
Answer:
18x-3
Step-by-step explanation:
f(x)= 3x + 10x
g(x)=5x - 3
f(x)+g(x) = 3x + 10x + 5x - 3
Combine like terms
= 18x -3
