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4 years ago

How is multiplication using partial products similar to regrouping

Mathematics

1 answer:

vodka [1.7K]4 years ago

4 0

Because you an in partial products you add the numbers like regrouping your still adding in regrouping

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Which is a point on the circle whose center is (0,0) and whose radius is 5? A. (0,0)

Temka [501]

Answer:

(3,4)

Step-by-step explanation:

x^2+y^2=(5)^2

if you graph it you will see that (3,4) is on the circle

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3 years ago

Y = 7/2x + 10 y = -7/2x - 1/10 these lines have perpendicular slopes. True or false?

forsale [732]

Answer: This is False because they don't go together and it doesn't make sense.

Step-by-step explanation:

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3 years ago

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What is an equation of the line that passes through the points (-8, 2) and (-4, -3)?

denpristay [2]

Answer:

y = (-6/13)x + (4/13).,

Step-by-step explanation:

the equation of the line is:

y = mx + b, where "m" is the slope and "b" gives the y-intercept

m = (y2 - y1)/(x2 - x1)

m = (-2 - 4)/(5 - (-8))

m = -6/13

y = (-6/13)x + b

the line passes through the point (-8,4) means that for x = -8, y = 4

4 = (-6/13)(-8) + b

b = 4 - (-6/13)(-8)

b = 4/13

the equation of the line that passes through the points (-8,4) and (5,-2) is:

y = (-6/13)x + (4/13).

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3 years ago

The figure shows a blueprint of a dining room, kitchen, and living room. Each square has a side length of 1/4 inch. Hardwood flo

scoray [572]

Answer:

there is no attachment

Step-by-step explanation:

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3 years ago

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A box contains 3 coins. One coin has 2 heads and the other two are fair. A coin is chosen at random from the box and flipped. If

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Answer: Our required probability is $\dfrac{1}{2}$

Step-by-step explanation:

Since we have given that

Number of coins = 3

Number of coin has 2 heads = 1

Number of fair coins = 2

Probability of getting one of the coin among 3 = $\dfrac{1}{3}$

So, Probability of getting head from fair coin = $\dfrac{1}{2}$

Probability of getting head from baised coin = 1

Using "Bayes theorem" we will find the probability that it is the two headed coin is given by

$\dfrac{\dfrac{1}{3}\times 1}{\dfrac{1}{3}\times \dfrac{1}{2}+\dfrac{1}{3}\times \dfrac{1}{2}+\dfrac{1}{3}\times 1}\\\\=\dfrac{\dfrac{1}{3}}{\dfrac{1}{6}+\dfrac{1}{6}+\dfrac{1}{3}}\\\\=\dfrac{\dfrac{1}{3}}{\dfrac{2}{3}}\\\\=\dfrac{1}{2}$

Hence, our required probability is $\dfrac{1}{2}$

No, the answer is not $\dfrac{1}{3}$

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3 years ago