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Brrunno [24]
2 years ago
7

Tyron takes 5/8 hour to paint a wall. His brother takes 1/3 of the time Tyron takes. How long will his brother take to paint 5 s

imilar walls.
Mathematics
1 answer:
suter [353]2 years ago
8 0
1/3 of tyron is 1/3 of 5/8=1/3 times 5/8=5/24 hour to paint 1 wall


5/24=1 wall
tmes 5 both sides
25/24=5 walll
about 1 and 1/24 wal;
about 1hr and 2.5mins
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kumpel [21]

Answer:

(x',y')-->(x-3,y-2)

Step-by-step explanation:

Notice that we can get from the x-coordinate of A, 1, to the x-coordinte of A', -2, by subtracting 3 from the x-coordinate of A. More formaly:

1+a=-2

a=-2-1

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Similarly, we can get from the y-coordinate of A, 5, to the y-coordinate of A', 3, by subtracting 2 from the y-coordinte of A. More formaly:

5+b=3

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Now we now that to get to A' from A, we need to subtract 3 to the x-coordinate of A and subtract 2 to the y-coordinate. Knowing this, we can create the expression to translate any point of the polygon ABCD to create the polygon A'B'C'D':

(x',y')-->(x-3,y-2)

3 0
3 years ago
Find 92% of 400 cars
mario62 [17]

Answer:

368

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
A seamstress uses 12 yards of fabric to make 3 costumes for students in the chorus. How many yards will she need to make costume
KIM [24]

Answer:

100 yards of fabric

Step-by-step explanation:

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3 years ago
claudia bought a television at a 25% discount . the original price of the television was $349. there wasa 7% sales tax. how much
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6 0
2 years ago
Justin is constructing a line through point Q that is perpendicular to line n. He has already constructed the arcs shown. He pla
krek1111 [17]
<span>B. It must be the same as when he constructed the arc centered at point A. This problem would be a lot easier if you had actually supplied the diagram with the "arcs shown". But thankfully, with a few assumptions, the solution can be determined. Usually when constructing a perpendicular to a line through a specified point, you first use a compass centered on the point to strike a couple of arcs on the line on both sides of the point, so that you define two points that are equal distance from the desired intersection point for the perpendicular. Then you increase the radius of the compass and using that setting, construct an arc above the line passing through the area that the perpendicular will go. And you repeat that using the same compass settings on the second arc constructed. This will define a point such that you'll create two right triangles that are reflections of each other. With that in mind, let's look closely at your problem to deduce the information that's missing. "... places his compass on point B ..." Since he's not placing the compass on point Q, that would imply that the two points on the line have already been constructed and that point B is one of those 2 points. So let's look at the available choices and see what makes sense. A .It must be wider than when he constructed the arc centered at point A. Not good. Since this implies that the arc centered on point A has been constructed, then it's a safe assumption that points A and B are the two points defined by the initial pair of arcs constructed that intersect the line and are centered around point Q. If that's the case, then the arc centered around point B must match exactly the setting used for the arc centered on point A. So this is the wrong answer. B It must be the same as when he constructed the arc centered at point A. Perfect! Look at the description of creating a perpendicular at the top of this answer. This is the correct answer. C. It must be equal to BQ. Nope. If this were the case, the newly created arc would simply pass through point Q and never intersect the arc centered on point A. So it's wrong. D.It must be equal to AB. Sorta. The setting here would work IF that's also the setting used for the arc centered on A. But that's not guaranteed in the description above and as such, this is wrong.</span>
8 0
3 years ago
Read 2 more answers
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