probability that a dessert sold at a certain cafe contains chocolate is 86%.
The probability that a dessert containing chocolate also contains nuts is 30%.
Find the probability that a dessert chosen at random contains nuts given that it contains chocolate
P(nuts given chocolate) = .30/.86 = .349 or 34
Answer:
97.5735
Step-by-step explanation:
Answer:
The width must be greater than 3 meters.
Step-by-step explanation:
Let w represent the width. Then 5w will represent the length, which is 5 times the width. The perimeter is the total of the side lengths of the rectangle, so is ...
P = 2w + 2(5w) = 12w
We want this to be greater than 36 m, so ...
P > 36 m
12w > 36 m . . . . . . . substitute our expression for P
w > 3 m . . . . . . . . . . divide by 12
The possible values for width are those values that are more than 3 meters.
A) is 28 response are recorded
B) there was only 24 students polled
C) A possible explanation for having more responses recorded than students polled is that they some may have played more than one sport.
Answer:
A
Step-by-step explanation:
