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Elis [28]
3 years ago
10

Ken predicts that the average temperature will be −5°C in December. If he predicts the temperature will rise 6°C in January and

fall 3°C in February, which of the following equations can he use to find the sum of the temperatures for those months? Check all that apply. [6 + 3] + 5 = 14 (–5) + [3 + 6] = –4 [(–5) + (–3)] + 6 = –2 5 + [(–6) + (–3)] = –4 [6 + (–5)] + (–3) = –2 [(–5) + 6 ] + (–3) = 4
Mathematics
1 answer:
ipn [44]3 years ago
7 0

Answer:

The equations [(-5) + (-3)] + 6 = -2 and [6 + (-5)] + (-3) = -2  he can use to find the sum of the temperatures for those months ⇒ 3rd , 5th

Step-by-step explanation:

i took the assignment

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Answer:

P(10 ≤ x ≤ 12) = 0.4274

Step-by-step explanation:

Population mean = u = 10

Population Standard Deviation = \sigma = 9

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Sample mean(\mu_{x}) is equal to the population mean. So,

Sample mean = \mu_{x} = 10

Sample standard deviation(\sigma_{x}) is equal to population standard deviation divided by square root of sample size. So,

Sample standard deviation = \sigma_{x} = \frac{9}{\sqrt{43}}=1.372

We have to find the probability that for a random sample of n = 43, the value lies between 10 and 12 i.e. P(10 ≤ x ≤ 12)

P(10 ≤ x ≤ 12) = P(x ≤ 12) - P( x ≤ 10)

We can find P(x ≤ 12 ) and P(x ≤ 10) by converting these values to z scores.

The formula for z score is:

z=\frac{x-\mu_{x}}{\sigma_{x}}

For x =12, we get:

z=\frac{12-10}{1.3725}=1.457

For x =10, we get:

z=\frac{10-10}{1.3725}=0

So,

P(x ≤ 12) - P( x ≤ 10) = P(z ≤ 1.457) - P(z ≤ 0)

From the z table,

P(z ≤ 1.457) = 0.9274

P(z ≤ 0) = 0.5

So,

P(x ≤ 12) - P( x ≤ 10) = P(z ≤ 1.458) - P(z ≤ 0) = 0.9274 - 0.5 = 0.4274

So,

P(10 ≤ x ≤ 12) = P(x ≤ 12) - P( x ≤ 10) = 0.4274

Therefore,

The probability that for a random sample of size 43, the mean lies between 10 and 12 is 0.4274.

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