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4 years ago

11

PLEASE HELP I'M DESPERATE <3

2 answers:

Iteru [2.4K]4 years ago

6 0

Start by simplifying all complex terms (anything term that can be broken down into an easier thing to work with). 4^2 is equal to 4x4 or 16, and the square root of 25 is 5. Now we have an expression that looks like this:

16-25x2

Using PEMDAS, we continue simplifying by multiplying 5 and two together, and then subtracting this from 16.

16-5x2
16-10
6

The value of this expression is 6.

Tomtit [17]4 years ago

5 0

4 squared = 16
Square root of 25 = 5
Equation = 16-5x2
Do 5x2 first because of order of operations
16-10 = 6

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3 years ago

S(3x – 7) + 5x = 8x + 1<br><br>x=

sergiy2304 [10]

Answer: -7s=1

Step-by-step explanation: Hope this helps

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3 years ago

Simplify as far as possible.<br> 7<br> √<br> 5<br> −<br> 3<br> √<br> 5

ElenaW [278]

Answer:

4 sqrt(5)

Step-by-step explanation:

7 sqrt(5) - 3 sqrt(5)

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3 years ago

What are the zeros of the quadratic function f(x) = 2x2 – 10x – 3?

Natasha2012 [34]

Answer:

$x=\frac{50+\sqrt{31}}{2},\frac{50-\sqrt{31}}{2}$ are zeroes of given quadratic equation.

Step-by-step explanation:

We have been a quadratic equation:

$2x^2-10x-3$

We need to find the zeroes of quadratic equation

We have a formula to find zeroes of a quadratic equation:

$x=\frac{b^2\pm\sqrt{D}}{2a}\text{where}D=\sqrt{b^2-4ac}$

General form of quadratic equation is $ax^2+bx+c$

On comparing general equation with b given equation we get

a=2,b=-10,c=-3

On substituting the values in formula we get

$D=\sqrt{(-10)^2-4(2)(-3)}$

$\Rightarrow D=\sqrt{100+24}=\sqrt{124}$

Now substituting D in $x=\frac{b^2\pm\sqrt{D}}{2a}$ we get

$x=\frac{(-10)^2\pm\sqrt{124}}{2\cdot 2}$

$x=\frac{100\pm\sqrt{124}}{4}$

$x=\frac{100\pm2\sqrt{31}}{4}$

$x=\frac{50\pm\sqrt{31}}{2}$

Therefore, $x=\frac{50+\sqrt{31}}{2},\frac{50-\sqrt{31}}{2}$

5 0

3 years ago

Read 2 more answers

What is the value of m?

valentinak56 [21]

Hey, Yeah the answer is 9 because
1/3(9)=12-9
3 = 3
They're equall

6 0

4 years ago