Imagine there are 4 sits for fill for the debate team
we can fill the first sit in 35 different ways, second sit we only have 34 choices , third sit 33 and last sit 32 ways to possible fill it.
35·34·33·32=1,256,640 possible ways the team could be form
Answer:
0.3898 = 38.98% probability that there will be 4 failures
Step-by-step explanation:
A sequence of Bernoulli trials forms the binomial probability distribution.
Binomial probability distribution
The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.
In which is the number of different combinations of x objects from a set of n elements, given by the following formula.
And p is the probability of X happening.
Let the probability of success on a Bernoulli trial be 0.26.
This means that
a. In five Bernoulli trials, what is the probability that there will be 4 failures?
Five trials means that
4 failures, so 1 success, and we have to find P(X = 1).
0.3898 = 38.98% probability that there will be 4 failures
Answer:
do 70x70=4,900 than do 100 x100=10,000 than add them to gether and you get 10,4900
Step-by-step explanation:
theres 2 sides not just one
M=-3.5+2t, R=-3t when they meet M=R so
-3.5+2t=-3t
-3.5+5t=0
5t=3.5
t=0.7 hrs (42 minutes)
1350 just multiply 30x45 and that the sender