Call (F) the age of the father and (J) the age of Julio
The F & J are related in this way: F=4J
Now you have a restriction in the form of inequality: The sum of both ages has to be greater or equal than 55.
Algebraically that is: F + J ≥ 55
You can substitute F with 4J to find the solution for J:
4J + J ≥ 55
5J ≥ 55
Now divide both sides by 5
5J/5 ≥ 55/5
J ≥ 11
That Imposes a lower boundary for the value of J of 11, meaning that the youngest age of Julio can be 11
Around 377 students would actually attend (according to the college estimates), off they admit in 580 students. If they want the most students they should admit their maximum.
Answer: 10+30=40 :)
Step-by-step explanation:
Answer:
1. move the constant to the right hand side to change its sign.
2.add the numbers.
3. using the absolute value definition rewrite the absolute value equation as two separate equations.
4.slove the equation for X
Step-by-step explanation:
it has two solutions
x=8
x= -9
the answer should be X1= 9, x2 =8
Answer:
Step-by-step explanation:
The formula for distance is:
Where (x₁, y) and (x₂, y₂) are the points.
We are given (-6, 6) and (-3, 3). If we match the value and its corresponding variable, we see that:
- x₁= -6
- y₁ = 6
- x₂ = -3
- y₂ = 3
Substitute the values into the formula.
Solve inside the parentheses.
- -3 --6 = -3+6 = 3
- 3-6 = -3
Solve the exponents.
- (3)²= 3*3= 9
- (-3)²= -3*-3 =9
Add.
Round to the nearest tenth. The 4 in the hundredth place tells us to leave the 2 in the tenth place.
The distance between the two points is apprximately <u>4.2</u>
