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Vlad1618 [11]
3 years ago
12

Which side in WXYZ corresponds to OP in MNOP A. XW B. XY C. YZ D. MN

Mathematics
1 answer:
SOVA2 [1]3 years ago
5 0

Answer:

Y and Z because just move the shape side ways and u can find the corresponding side.

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Can somebody solve this?
erastova [34]

Answer:

∠ABC = 46°

Step-by-step explanation:

DB and BC are of same length (radius), making it an isosceles triangle.

The base of the triangle is the same at 23°, a total of 46°.

180° - 46° = 134°

But we need ∠ABC, and since points DBA lie on the circumference, it's a straight line.

Therefore, 180° - 134° = 46°

7 0
3 years ago
Find the zero of the function:<br> y= 11x^2+25x-24
Ann [662]
X=8/11,-3 is the answer to your question.
4 0
3 years ago
In the figure below, \overline{AD} AD start overline, A, D, end overline and \overline{BE} BE start overline, B, E, end overline
VLD [36.1K]

Answer:

<u>The measure of the arc CD = 64°</u>

Step-by-step explanation:

It is required to find the measure of the arc CD in degrees.

So, as shown at the graph

BE and AD are are diameters of circle P

And ∠APE is a right angle ⇒ ∠APE = 90°

So, BE⊥AD

And so, ∠BPE = 90° ⇒(1)

But it is given: ∠BPE = (33k-9)° ⇒(2)

From (1) and (2)

∴ 33k - 9 = 90

∴ 33k = 90 + 9 = 99

∴ k = 99/33 = 3

The measure of the arc CD = ∠CPD = 20k + 4

By substitution with k

<u>∴ The measure of the arc CD = 20*3 + 4 = 60 + 4 = 64°</u>

6 0
3 years ago
A certain math teachers likes to keep a box of prizes to distribute to students. The math teacher likes to keep at least twice a
Law Incorporation [45]

Option C

Math teacher would need to buy 130 prizes

<em><u>Solution:</u></em>

Given that,

Math teacher currently has 109 students and the box has 88 prizes in it

The math teacher likes to keep at least twice as many prizes in the box as she has students

So, she wants the number of prizes to be twice the number of students

Therefore,

number of prizes = 2 x 109 students

number of prizes = 2 x 109 = 218 prizes

The box has 88 prizes in it

Therefore, number of prizes she would need to buy is:

⇒ 218 - 88 = 130

Thus she would need to buy 130 prizes

3 0
3 years ago
a ladder leans against the sufe of a house. the angle of elevation of the ladder is 70 degrees when the bottom of the ladder is
nekit [7.7K]

Answer:

≈ 35.1 ft

Step-by-step explanation:

The model is a right triangle with ladder being the hypotenuse and the angle between the ground and the ladder is 70°

Using the cosine ratio, with l being the length of the ladder.

cos70° = \frac{adjacent}{hypotenuse} = \frac{12}{l} ( multiply both sides by l )

l × cos70° = 12 ( divide both sides by cos70° )

l = \frac{12}{cos70} ≈ 35.1 ( to the nearest tenth )

The ladder is approx 35.1 ft long

4 0
3 years ago
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