Answer:
∠ABC = 46°
Step-by-step explanation:
DB and BC are of same length (radius), making it an isosceles triangle.
The base of the triangle is the same at 23°, a total of 46°.
180° - 46° = 134°
But we need ∠ABC, and since points DBA lie on the circumference, it's a straight line.
Therefore, 180° - 134° = 46°
X=8/11,-3 is the answer to your question.
Answer:
<u>The measure of the arc CD = 64°</u>
Step-by-step explanation:
It is required to find the measure of the arc CD in degrees.
So, as shown at the graph
BE and AD are are diameters of circle P
And ∠APE is a right angle ⇒ ∠APE = 90°
So, BE⊥AD
And so, ∠BPE = 90° ⇒(1)
But it is given: ∠BPE = (33k-9)° ⇒(2)
From (1) and (2)
∴ 33k - 9 = 90
∴ 33k = 90 + 9 = 99
∴ k = 99/33 = 3
The measure of the arc CD = ∠CPD = 20k + 4
By substitution with k
<u>∴ The measure of the arc CD = 20*3 + 4 = 60 + 4 = 64°</u>
Option C
Math teacher would need to buy 130 prizes
<em><u>Solution:</u></em>
Given that,
Math teacher currently has 109 students and the box has 88 prizes in it
The math teacher likes to keep at least twice as many prizes in the box as she has students
So, she wants the number of prizes to be twice the number of students
Therefore,
number of prizes = 2 x 109 students
number of prizes = 2 x 109 = 218 prizes
The box has 88 prizes in it
Therefore, number of prizes she would need to buy is:
⇒ 218 - 88 = 130
Thus she would need to buy 130 prizes
Answer:
≈ 35.1 ft
Step-by-step explanation:
The model is a right triangle with ladder being the hypotenuse and the angle between the ground and the ladder is 70°
Using the cosine ratio, with l being the length of the ladder.
cos70° = 
= 
( multiply both sides by l )
l × cos70° = 12 ( divide both sides by cos70° )
l = 
≈ 35.1 ( to the nearest tenth )
The ladder is approx 35.1 ft long
