Someone pls help with geometryyy

Mathematics

1 answer:

andrezito [222]4 years ago

5 0

What's the problem about geometry? Which section?

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I have no idea how to even begin with this

Leviafan [203]

We have two similar triangles, the one as a whole and the one inside of it. To calculate the height of the flagpole we can set up a proportion. First calculate the length of the base of the smaller triangle.

16.60 - 12.45 = 4.15m

The height is 1.65m, set up a proportion:

$\sf\dfrac{1.65}{4.15}=\dfrac{x}{16.60}$

Cross multiply:

$\sf 27.39=4.15x$

Divide 4.15 to both sides:

$\sf x=\boxed{\sf 6.6m}$

So the height of the flagpole is 6.6 meters tall.

5 0

4 years ago

Please I need help with this ASAP

MArishka [77]

$\bf \begin{array}{ccll} term&value\\ \cline{1-2} s_4&18\\ s_5&18r\\ s_6&18rr\\ &18r^2 \end{array}\qquad \qquad \stackrel{s_6}{8}=18r^2\implies \cfrac{8}{18}=r^2\implies \cfrac{4}{9}=r^2 \\\\\\ \sqrt{\cfrac{4}{9}}=r\implies \cfrac{\sqrt{4}}{\sqrt{9}}=r\implies \boxed{\cfrac{2}{3}=r} \\\\[-0.35em] ~\dotfill$

$\bf n^{th}\textit{ term of a geometric sequence} \\\\ s_n=s_1\cdot r^{n-1}\qquad \begin{cases} s_n=n^{th}\ term\\ n=\textit{term position}\\ s_1=\textit{first term}\\ r=\textit{common ratio}\\ \cline{1-1} n=6\\ s_6=8\\ r=\frac{2}{3} \end{cases}\implies 8=s_1\left( \frac{2}{3} \right)^{6-1} \\\\\\ 8=s_1\left( \frac{2}{3} \right)^5\implies 8=s_1\cdot \cfrac{32}{243}\implies 8\cdot \cfrac{243}{32}=s_1\implies \boxed{\cfrac{243}{4}=s_1}$