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stira [4]
4 years ago
6

which statement best describes the graph of x3 − 3x2 − 4x 12? it starts down on the left and goes up on the right and intersects

the x-axis at x = −2, 2, and 3. it starts down on the left and goes up on the right and intersects the x-axis at x = −2, 4, and 3. it starts up on the left and goes down on the right and intersects the x-axis at x = −2, 2, and 3. it starts up on the left and goes down on the right and intersects the x-axis at x = −2, 4, and 3.

Mathematics
2 answers:
trapecia [35]4 years ago
6 0
It starts down on the left and goes up on the right and intersects the x-axis at x = −2, 2, and 3

Because the roots are -2, 2 and 3 and the function is negative when x is a less than - 2.
professor190 [17]4 years ago
5 0

Answer:

option A is correct.

Step-by-step explanation:

We are given the graph of x^{3}-3x^{2}-4x+12.

clearly the roots of this equation is:

x^3-3x^2-4x+12=0\\x^2(x-3)-4(x-3)=0\\(x^2-4)(x-3)=0\\(x-2)(x+2)(x-3)=0

⇒  x=2,x=-2and x=3 are the roots of the equation.

Hence the graph will intersect x-axis at these 3 points x=3,2 and -2.


From the graph we could clearly see that the graph starts down on the left and goes up on the right and intersects the x-axis at x=2,-2 and 3.

Hence, option A is correct.




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Question
Kay [80]

Answer:

f(x)=2(x-2)(x^2+64)

Step-by-step explanation:

A standard polynomial in factored form is given by:

f(x)=a(x-p)(x-q)...

Where <em>p</em> and <em>q</em> are the zeros.

We want to find a third-degree polynomial with zeros <em>x</em> = 2 and <em>x </em>= -8i and equals 320 when <em>x </em>= 4.

First, by the Complex Root Theorem, if <em>x</em> = -8i is a root, then <em>x </em>= 8i must also be a root.

Therefore, we acquire:

f(x)=a(x-(2))(x-(-8i))(x-(8i))

Simplify:

f(x)=a(x-2)(x+8i)(x-8i)

Expand the second and third factors:

=(x+8i)x+(x+8i)(-8i)\\\\=(x^2+8ix)+(-8ix-64i^2)\\\\=(x^2)+(8ix-8ix)+(-64i^2)\\\\=x^2-64(-1)\\\\ =x^2+64

Hence, our function is now:

f(x)=a(x-2)(x^2+64)

It equals 320 when <em>x</em> = 4. Therefore:

320=a(4-2)(4^2+64)

Solve for <em>a</em>. Evaluate:

320=(2)(80)a

So:

320=160a\Rightarrow a=2

Our third-degree polynomial equation is:

f(x)=2(x-2)(x^2+64)

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