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3 years ago

What is 5(2x+8)-5x=5(5x+6?

Mathematics

1 answer:

yanalaym [24]3 years ago

4 0

5(2x+8)-5x=5(5x+6)

Distribute

10x+40-5x=25x+30

combine like terms

5x+40=25x+30

-5x -5x

subtract 5x from both sides

40=20x+30

-30 -30

subtract 30 from both sides

10=20x

÷20 ÷20

divide both sides by 20

1/2=x is your final answer

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What is the equation of the axis of symmetry?

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3 years ago

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2 years ago

PLS ANSWER QUICK! Thanks!

ziro4ka [17]

Answer:

The correct answer would be $a=\sqrt{c^2-b^2}$

Step-by-step explanation:

given $a^2+b^2=c^2$ we want to solve for a

How?

We can do this by using basic algebra ( isolating the variable (a ))

Step 1 subtract $b^2$ from each side

$a^2+b^2-b^2=a^2\\c^2-b^2=c^2-b^2$

now we have $a^2=c^2-b^2$

step 2 take the square root of each side

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we're left with $a=\sqrt{c^2-b^2}$

Hence your answer is A

5 0

2 years ago

Evaluate the surface integral. s x2 + y2 + z2 ds s is the part of the cylinder x2 + y2 = 4 that lies between the planes z = 0 an

Leya [2.2K]

Parameterize the lateral face $T_1$ of the cylinder by

$\mathbf r_1(u,v)=(x(u,v),y(u,v),z(u,v))=(2\cos u,2\sin u,v$

where $0\le u\le2\pi$ and $0\le v\le3$ , and parameterize the disks $T_2,T_3$ as

$\mathbf r_2(r,\theta)=(x(r,\theta),y(r,\theta),z(r,\theta))=(r\cos\theta,r\sin\theta,0)$
$\mathbf r_3(r,\theta)=(r\cos\theta,r\sin\theta,3)$

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$=\displaystyle2\int_{u=0}^{u=2\pi}\int_{v=0}^{v=3}(v^2+4)\,\mathrm dv\,\mathrm du+\int_{r=0}^{r=2}\int_{\theta=0}^{\theta=2\pi}r^3\,\mathrm d\theta\,\mathrm dr+\int_{r=0}^{r=2}\int_{\theta=0}^{\theta=2\pi}r(r^2+9)\,\mathrm d\theta\,\mathrm dr$
$=\displaystyle4\pi\int_{v=0}^{v=3}(v^2+4)\,\mathrm dv+2\pi\int_{r=0}^{r=2}r^3\,\mathrm dr+2\pi\int_{r=0}^{r=2}r(r^2+9)\,\mathrm dr$
$=136\pi$

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3 years ago

At a toll booth, an attendant found that for every 5 vehicles that passed through the toll, 2 were trucks.

kompoz [17]

Answer:

Step-by-step explanation:

5-2=3

other vehicles:Trucks::3:2

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3 years ago