Answer:
768 bugs
Step-by-step explanation:
You can rewrite this problem as a function as time where the bug population is f(x), and x is the number of days since the start.
f(x)=6*2^(x/5)
Here, the 6 represents the number of bugs that you start with, the two shows that they double every day, and the /5 shows that they double every 5 days.
By plugging in 35, you get 6*2^7, which is 768.
Let us assume the unknown number = x
Now we have to follow the details given in the question to bring out the actual equation. In this case there will be only one equation.
(x/3)^2 - (2x + 7) = 0
(x/3)^2 = 2x + 7
x^2/9 = 2x + 7
x^2 = 9(2x + 7)
x^2 = 18x + 63
x^2 - 18x = 63
This would be the final equation for the given problem. his problem needs any solver to understand the words very minutely.
5)

6)

7)
slope as you should already know is rise/run, or how much something moves in relation something else, namely how much the y-axis go up as the x-axis moves sideways, one moves, the other follows, but the increments will be different, sometimes the same, but usually different.
the y-intercept means, when the graph of the equation touches or intercepts the y-axis, and when that happens x = 0, or the horizontal distance is at bay.
for the slope on 6), 30 or 30/1 means, for every 1 year(x) passed, the worth(y) increased by 30, or jumped by 30 units, so as the x-axis moved 1, the y-axis moved 30. After 12 years 30 * 12 = 360, and we add the initial 720 and we end up with 1080.
the y-intercept, well, as aforementioned is when x = 0, is year 0.
The range is the difference between the highest and lowest pays.
Highest pay: GS-5 - 2,252
Lowest pay: GS-1 - 1,461
Range = 2252 - 1461 = 791
The answer is D. $791