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zubka84 [21]
3 years ago
6

Find the measurement of the missing angles in each triangle. Explain your steps.

Mathematics
1 answer:
timurjin [86]3 years ago
3 0

Answer:

31 degrees and 26 degrees

Step-by-step explanation:

Every triangles' angles equals 180 degrees.

180 - 82 - 67 = 31

180 - 80 - 74 = 26

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Find the equation of the line.<br> Use exact numbers.<br> y =<br> X +
puteri [66]

Answer:

y =  \frac{3}{4} x - 2

Step-by-step explanation:

Remmeber this:

slope =  \frac{rise}{run}

The y-intercept is where the lone goes through the y-axis.

5 0
2 years ago
Solve the equation sin theta = 0.3 to the nearest tenth. Use the restrictions 90degrees &lt; theta &lt; 180degrees.
Alexxandr [17]
We first do:
∅ = sin⁻¹(0.3)
∅ = 17.5°

To go into the second quadrant, we add 90°.
∅ = 17.5 + 90
= 107.5°
The answer is A.
5 0
3 years ago
Sam has 4/5 ounces of butter in his refrigerator. If it takes 1/8 ounces to make a cupcake, how many cupcakes can Sam make?
Grace [21]
4/5 divided by 1/8
= 4/5 x 8/1
32/5
= 6.4 cupcakes or 6 cupcakes if they’re looking for a whole number
7 0
3 years ago
The school is planting a circular garden. If the
Tatiana [17]

Answer:

<u>The area of the circular garden is 28.3 square feet</u>

Step-by-step explanation:

Let's recall that the area of a circle is π * r², therefore if the diameter of the circular garden is 6 feet, the area is:

Diameter = 6 feet ⇒ radius = (6/2) = 3 feet

Area of the circular garden = π * 3²

Area of the circular garden = 3.1416 * 9

Area of the circular garden = 28.2744

<u>Area of the circular garden = 28.3 square feet</u>

8 0
3 years ago
After being treated with chemotherapy, the radius of the tumor decreased by 23%. What is the corresponding percentage decrease i
Crazy boy [7]

Answer:

The volume of the tumor experimented a decrease of 54.34 percent.

Step-by-step explanation:

Let suppose that tumor has an spherical geometry, whose volume (V) is calculated by:

V = \frac{4\pi}{3}\cdot R^{3}

Where R is the radius of the tumor.

The percentage decrease in the volume of the tumor (\%V) is expressed by:

\%V = \frac{\Delta V}{V_{o}} \times 100\,\%

Where:

\Delta V - Absolute decrease in the volume of the tumor.

V_{o} - Initial volume of the tumor.

The absolute decrease in the volume of the tumor is:

\Delta V = V_{o}-V_{f}

\Delta V = \frac{4\pi}{3}\cdot (R_{f}^{3}-R_{o}^{3})

The percentage decrease is finally simplified:

\%V = \left[1-\left(\frac{R_{f}}{R_{o}}\right)^{3} \right]\times 100\,\%

Given that R_{o} = R and R_{f} = 0.77\cdot R, the percentage decrease in the volume of tumor is:

\%V = \left[1-\left(\frac{0.77\cdot R}{R}\right)^{3} \right]\times 100\,\%

\%V = 54.34\,\%

The volume of the tumor experimented a decrease of 54.34 percent.

5 0
3 years ago
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