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4 years ago

The further the planets is from the sun the is its year

Physics

1 answer:

Genrish500 [490]4 years ago

7 0

The further the planet is from the sun the smaller the year is

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What is the cost of operating a 100 W light bulb for "4 hrs per day" for 30 days, if the cost of electricity is 6 cents kW•h

Sidana [21]

Answer:

the cost of operating the light bulb is 72 cents.

Explanation:

Given;

cost of electricity, C = 6 cents / kW.h

power of light bulb, P = 100 W

time of light power consumption, t = 4 hours per day for 30 days

total time = 4 hours x 30 = 120 hours

Power consumed by the light bulb is calculated as;

P = 100 x 120 = 12000 w.h = 12 kW.h

Cost of power consumption = 6 cents/kWh x 12 kWh

= 72 cents

Therefore, the cost of operating the light bulb is 72 cents.

3 0

3 years ago

The second hand on a clock is 3.00 cm long. What is the speed of the outermost tip of that second hand

Gnom [1K]

In 60 minutes or 3600 seconds, the tip of the minute hand traverses the circumference of a circle with radius 3.00 cm, so it moves with a tangential speed of

(3.00 cm)/(3600 s) ≈ 0.00083 cm/s = 8.3 μm/s

4 0

3 years ago

A 1.6-lb collar is attached to a spring and slides without friction along a circular rod in a vertical plane. The spring has an

romanna [79]

Answer:

k = 652 lb/ft

Explanation:

Given :

Weight of the collar = 1.6 lb

The upstretched length of the spring = 6 in

Speed = 16 ft/s

PA = 8 + 10

= 18 inch

Let the initial elongation be $\Delta x_i$

∴ $\Delta x_i$ = 18 - 6

= 12 inch = 1 foot

$PB = \sqrt{13^2+5^2}$

= 13.925 inch

Final elongation in the spring

$\Delta x_B = 7.928$ inch = 0.66 feet

Applying the conservation of the mechanical energy between A and B is

$K.E_A+P.E_{g,A}+P.E_{sp,A}= K.E_B+P.E_{g,B}+P.E_{sp,B}$

$0+mg_r+\frac{1}{2}k(\Delta x_i)^2=\frac{1}{2}mv_B^2+0+\frac{1}{2}k(\Delta x_B)^2$

$\frac{1}{2}k[(1)^2-(0.66)^2]=\frac{1.6}{2}\times (16)^2-1.6 \times 32 \times \frac{5}{12}$

$0.281 \ k =204.8-21.33$

k = 652 lb/ft

5 0

3 years ago

30 minus 3 plus 4 is equal to what

Pepsi [2]

Answer:

Explanation:

quick maths

6 0

3 years ago

Read 2 more answers

The construction of a flat rectangular roof (6.17 m × 5.92 m) allows it to withstand a maximum net outward force of 2.00 × 104 N

Blababa [14]

Answer:

$v_2=29.13\ m/s$

Explanation:

It is given that,

Dimension of the rectangular roof, (6.17 m × 5.92 m)

The maximum net outward force, $F=2\times 10^4\ N$

The density of air, $\rho=1.29\ kg/m^3$

The Bernoulli equation is used to find wind speed of this roof blow outward. It is given by :

$P_1+\dfrac{1}{2}\rho v_1^2=P_2+\dfrac{1}{2}\rho v_2^2$

Here, $v_1=0$ (since air inside the roof is not moving)

$v_2=\sqrt{\dfrac{2(P_1-P_2)}{\rho}}$

Since, $F=(P_1-P_2)A$

$v_2=\sqrt{\dfrac{2F}{\rho A}}$

$v_2=\sqrt{\dfrac{2\times 2\times 10^4}{1.29\times 6.17\times 5.92 }}$

$v_2=29.13\ m/s$

So, the wind speed of this roof blow outward is 29.13 m/s. Hence, this is the required solution.

5 0

4 years ago