All categories

3 years ago

What is the cost of operating a 100 W light bulb for "4 hrs per day" for 30 days, if the cost of electricity is 6 cents kW•h

Physics

1 answer:

Sidana [21]3 years ago

3 0

Answer:

the cost of operating the light bulb is 72 cents.

Explanation:

Given;

cost of electricity, C = 6 cents / kW.h

power of light bulb, P = 100 W

time of light power consumption, t = 4 hours per day for 30 days

total time = 4 hours x 30 = 120 hours

Power consumed by the light bulb is calculated as;

P = 100 x 120 = 12000 w.h = 12 kW.h

Cost of power consumption = 6 cents/kWh x 12 kWh

= 72 cents

Therefore, the cost of operating the light bulb is 72 cents.

You might be interested in

in which type of wave are vibrations at right angles to the direction in which the wave is travelling

Pani-rosa [81]

Answer:

longitudinal waves have those properties

7 0

3 years ago

Consider a container of oxygen gas at a temperature of 23°C that is 1.00 m tall. Compare the gravitational potential energy of a

Sergio039 [100]

Answer:

Yes, it is reasonable to neglect it.

Explanation:

Hello,

In this case, a single molecule of oxygen weights 32 g (diatomic oxygen) thus, the mass of kilograms is (consider Avogadro's number):

$m=1molec*\frac{1mol}{6.022x10^{23}molec} *\frac{32g}{1mol}*\frac{1kg}{1000g}=5.31x10^{-26}kg$

After that, we compute the potential energy 1.00 m above the reference point:

$U=mhg=5.31x10^{-26}kg*1.00m*9.8\frac{m}{s^2}=5.2x10^{-25}J$

Then, we compute the average kinetic energy at the specified temperature:

$K=\frac{3}{2}\frac{R}{Na}T$

Whereas $N_A$ stands for the Avogadro's number for which we have:

$K=\frac{3}{2} \frac{8.314\frac{J}{mol*K}}{6.022x10^{23}/mol}*(23+273)K\\ \\K=6.13x10^{-21}J$

In such a way, since the average kinetic energy energy is about 12000 times higher than the potential energy, it turns out reasonable to neglect the potential energy.

Regards.

8 0

4 years ago

If the truck has a mass of 2,000 kilograms , what's its momentum?(v=35 m/s)

katen-ka-za [31]

Answer:

$\boxed {\boxed {\sf 70,000 \ kg*m/s}}$

Explanation:

Momentum is the product of mass and velocity.

$p=m*v$

The mass of the truck is 2,000 kilograms and the velocity is 35 meters per second.

$m= 2000 \ kg \\v= 35 \ m/s$

Substitute the values into the formula and multiply.

$p= 2000 \ kg * 35 \ m/s \\p= 70,000 \ kg*m/s$

The truck's momentum is <u>70,000 kilograms meters per second.</u>

8 0

3 years ago

Why is a virus NOT classified as a living thing?

Shkiper50 [21]

The correct answer would be B. A virus is living BUT however it does NOT have all of the 7 characteristics of life.

Hope that helped ^^

4 0

3 years ago

Read 2 more answers

f an arrow is shot upward on the moon with velocity of 35 m/s, its height (in meters) after t seconds is given by h(t)=35t−0.83t

inysia [295]

Answer:

The velocity of the arrow after 3 seconds is 30.02 m/s.

Explanation:

It is given that,

An arrow is shot upward on the moon with velocity of 35 m/s, its height after t seconds is given by the equation:

$h(t)=35t-0.83t^2$

We know that the rate of change of displacement is equal to the velocity of an object.

$v(t)=\dfrac{dh(t)}{dt}\\\\v(t)=\dfrac{d(35t-0.83t^2)}{dt}\\\\v(t)=35-1.66t$

Velocity of the arrow after 3 seconds will be :

$v(t)=35-1.66t\\\\v(t)=35-1.66(3)\\\\v(t)=30.02\ m/s$

So, the velocity of the arrow after 3 seconds is 30.02 m/s. Hence, this is the required solution.

7 0

3 years ago