All right angle triangles have a 90 degree angle. 90+42=132
All triangles have angles that add up to 180 degrees 180-132=48
90+42=132
180-132=48
<span>The missing angle is 48°</span>
2 sides and 1 angle I think...
The answer is 7*5*3*4=420
Answer:
It has one solution which is a=1
AAS Postulate
It is given that CE = BD so we know "S" (representing side) has to be in the three letter postulate.
It is also given that angle DBA and angle CEA are right angles, so therefore they are congruent. Now we know that an "A" must also be in the postulate.
Lastly, we know that the triangles have a second angle, EAB, in common because they share it overlappingly. So there must be another "A" in the postulate.
Now we need to look at the order in which it is presented. The order follows Angle, Angle, Side so the postulate must be the AAS postulate. Hope this helps!