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KATRIN_1 [288]
3 years ago
8

−5y+8x=−18 5y+2x=58 Solve the system of equations. ​

Mathematics
1 answer:
kvasek [131]3 years ago
8 0

Answer:

1:   −5y+8x=−18  

Slope = 3.200/2.000 = 1.600

 x-intercept = -18/8 = -9/4 = -2.25000

 y-intercept = 18/5 = 3.60000

2:   Slope = -0.800/2.000 = -0.400

 x-intercept = 58/2 = 29

 y-intercept = 58/5 = 11.60000

Step-by-step explanation:

1: Step  1  :

Equation of a Straight Line

1.1     Solve   -5y+8x+18  = 0

Tiger recognizes that we have here an equation of a straight line. Such an equation is usually written y=mx+b ("y=mx+c" in the UK).

"y=mx+b" is the formula of a straight line drawn on Cartesian coordinate system in which "y" is the vertical axis and "x" the horizontal axis.

In this formula :

y tells us how far up the line goes

x tells us how far along

m is the Slope or Gradient i.e. how steep the line is

b is the Y-intercept i.e. where the line crosses the Y axis

The X and Y intercepts and the Slope are called the line properties. We shall now graph the line  -5y+8x+18  = 0 and calculate its properties

Graph of a Straight Line :

 

 

Calculate the Y-Intercept :

Notice that when x = 0 the value of y is 18/5 so this line "cuts" the y axis at y= 3.60000

 y-intercept = 18/5  =  3.60000  

Calculate the X-Intercept :

When y = 0 the value of x is -9/4 Our line therefore "cuts" the x axis at x=-2.25000

 x-intercept = -18/8 = -9/4  = -2.25000  

Calculate the Slope :

Slope is defined as the change in y divided by the change in x. We note that for x=0, the value of y is 3.600 and for x=2.000, the value of y is 6.800. So, for a change of 2.000 in x (The change in x is sometimes referred to as "RUN") we get a change of 6.800 - 3.600 = 3.200 in y. (The change in y is sometimes referred to as "RISE" and the Slope is m = RISE / RUN)

2: Same thing

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Answer:

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10(-3n + 8) = 380

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The function f(x) = –x2 – 4x + 5 is shown on the graph. On a coordinate plane, a parabola opens down. It goes through (negative
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<h3>Which statements are true?</h3>

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Brady made a scale drawing of a rectangular swimming pool on a coordinate grid. The points (-20, 25), (30, 25), (30, -10) and (-
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Answer:

Length = 50 units

width = 35 units

Step-by-step explanation:

Let A, B, C and D be the corner of the pools.

Given:

The points of the corners are.

A(x_{1}, y_{1}})=(-20, 25)

B(x_{2}, y_{2}})=(30, 25)

C(x_{3}, y_{3}})=(30, -10)

D(x_{4}, y_{4}})=(-20, -10)

We need to find the dimension of the pools.

Solution:

Using distance formula of the two points.

d(A,B)=\sqrt{(x_{2}-x_{1})^{2}+(y_{2}-y_{1})^{2}}----------(1)

For point AB

Substitute points A(30, 25) and B(30, 25) in above equation.

AB=\sqrt{(30-(-20))^{2}+(25-25)^{2}}

AB=\sqrt{(30+20)^{2}}

AB=\sqrt{(50)^{2}

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Similarly for point BC

Substitute points B(-20, 25) and C(30, -10) in equation 1.

d(B,C)=\sqrt{(x_{3}-x_{2})^{2}+(y_{3}-y_{2})^{2}}

BC=\sqrt{(30-30)^{2}+((-10)-25)^{2}}

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Similarly for point DC

Substitute points D(-20, -10) and C(30, -10) in equation 1.

d(D,C)=\sqrt{(x_{3}-x_{4})^{2}+(y_{3}-y_{4})^{2}}

DC=\sqrt{(30-(-20))^{2}+(-10-(-10))^{2}}

DC=\sqrt{(30+20)^{2}}

DC=\sqrt{(50)^{2}}

DC = 50 units

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Substitute points A(-20, 25) and D(-20, -10) in equation 1.

d(A,D)=\sqrt{(x_{4}-x_{1})^{2}+(y_{4}-y_{1})^{2}}

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AD=\sqrt{(-20+20)^{2}+(-35)^{2}}

AD=\sqrt{(-35)^{2}}

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Therefore, the dimension of the rectangular swimming pool are.

Length = 50 units

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Check: L = 3(8)

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