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vekshin1
3 years ago
9

Help please please please

Mathematics
1 answer:
madam [21]3 years ago
4 0

Answer: I think that the answer is 1,944 I think

Step-by-step explanation:  216 x 3 = 1,944

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Tameka bought three dozen donuts to take into work. There are 15 cake donuts, 6 glazed donuts, 6 chocolate donuts, and 9 blueber
Leya [2.2K]
Ratio of Cake Donuts to Total Donuts = 15/36

Let, the number of people with Cake donuts = x

Then, 15/36 = x/12

x = 12/36 * 15

x = 1/3 * 15

x = 5

In short, Your Answer would be: 5

Hope this helps!
5 0
3 years ago
Read 2 more answers
Which of the following sets are closed under multiplication? Select all that apply.
ivolga24 [154]

Answer:

Integers, whole numbers and polynomials are sets of closed under multiplication.

Only Irrational numbers are not the sets of closed under multiplication.                  

Step-by-step explanation:

To find : Which of the following sets are closed under multiplication?

1. Integers  

Yes, integers is a sets of closed under multiplication as if you multiply an integer by an integer, you will always get another  integer.

Example - 3\times 3=9 is an integer

2. Irrational numbers


No, irrationals are not closed under multiplication.

Example - \sqrt{3} \times \sqrt{3} =3 is a rational number

3. Whole numbers


Yes, whole numbers is a sets of closed under multiplication as if you multiply a whole number by a whole number, you will always get another  whole number.

Example - 5\times 5=25 is a whole number

4. Polynomials

Yes, polynomial is sets of closed under multiplication as if you multiply the variables' exponents are added, and the exponents in polynomials are whole numbers so the new exponents will be whole numbers.

Example - (x + 1)(x^2 + 4x + 3) = x^3 + 5x^2 + 7x + 3 is a polynomial.


4 0
3 years ago
Read 2 more answers
Helpi accendintly made the question I just posted 5 points but this one is 50
Umnica [9.8K]

(a) For any probability distribution, the total probability must be 1. That is, the area under the probability density curve must be equal to 1.

The empirical rule for normal distributions says

• approximately 68% of the distribution lies within 1 standard deviation of the mean

• approx. 95% lies within 2 s.d. of the mean

• approx. 99.7% lies within 3 s.d. of the mean

In this case, with mean 3500 and s.d. 470, this translates to

• Pr(3500 - 470 < X < 3500 + 470) = Pr(3030 < X < 3970) ≈ 0.68

• Pr(3500 - 2*470 < X < 3500 + 2*470) = Pr(2560 < X < 4440) ≈ 0.95

• Pr(3500 - 3*470 < X < 3500 + 3*470) = Pr(2090 < X < 4910) ≈ 0.997

Continuous probability distributions also have the property that

Pr(a < X < b) = Pr(a < X < c) + Pr(c < X < b)

if a < c < b.

Combining all these properties, we can find the probabilities for each of the 8 regions in the graph to be (from left to right)

• Pr(-∞ < X < 2090) ≈ (1 - 0.997)/2 ≈ 0.0015

• Pr(2090 < X < 2560) ≈ (1 - 0.95 - 2*0.0015)/2 ≈ 0.0235

• Pr(2560 < X < 3030) ≈ (1 - 0.68 - 2*0.0235 - 2*0.0015)/2 ≈ 0.135

• Pr(3030 < X < 3500) ≈ 0.68/2 ≈ 0.34

and since the distribution is symmetric about its mean, we already know the remaining probabilities,

• Pr(3500 < X < 3970) ≈ 0.34

• Pr(3970 < X < 4440) ≈ 0.135

• Pr(4440 < X< 4910) ≈ 0.0235

• Pr(4910 < X < ∞) ≈ 0.0015

(b) Per the rule, 99.7% of babies would weight between 2090 and 4910 grams.

(c) The proportion of babies weighing less than 3030 grams is the sum of the proportions of babies weighing less than 2090, between 2090 and 2560, and between 2560 and 3030 grams. So

Pr(X < 3030) = Pr(-∞ < X < 2090) + Pr(2090 < X < 2560) + P(2560 < X < 3030)

Pr(X < 3030) ≈ 0.0015 + 0.0235 + 0.135

Pr(X < 3030) ≈ 0.16 = 16%

(d) Similarly,

Pr(X > 2560) = Pr(2560 < X < 3030) + Pr(3030 < X < 3500) + … + Pr(4910 < X < ∞)

Pr(X > 2560) ≈ 0.135 + 0.34 + 0.34 + 0.135 + 0.0235 + 0.0015

Pr(X > 2560) ≈ 0.975 = 97.5%

8 0
3 years ago
What is the opposite
Rus_ich [418]
I think the answer is 10/7 or 3.82
7 0
3 years ago
Can someone help me answer the above question paper​
Oxana [17]

Answer:

need teachers help with this one

Step-by-step explanation:

7 0
3 years ago
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