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3 years ago

Use the distributive property to write2(-5 + 3) as an equivalent expression what is the value of the expression

Mathematics

1 answer:

KiRa [710]3 years ago

4 0

Answer:

-10+6=-4

Step-by-step explanation:

Here's why we use distributive property, so a(b+c) = ab+ac, therefore 2(-5+3) is -10+6, which is equal to -4.

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kondor19780726 [428]

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Step-by-step explanation:

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2 years ago

What does point b represent on the graph ?

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Answer:

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3 years ago

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Solve for x.<br> 2x² +21x-61 = (x+7)²<br><br> Please

Ymorist [56]

Answer:

$x = \frac{-7 +\sqrt{489} }{2}$

$x = \frac{-7 - \sqrt{489} }{2}$

Step-by-step explanation:

2x² +21x-61 = (x+7)²

expand

2x² + 21x - 61 = x² + 14x +49

move everything to one side

x² + 7x - 12 = 0

use quadratic formula

$x = \frac{-b +- \sqrt{b^{2}-4ac } }{2a}$

plug in the values

$x = \frac{-7 +- \sqrt{7^{2}-4(1)(-110) } }{2(1)}$

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$x = \frac{-7 +- \sqrt{49-4(1)(-110) } }{2}$

$x = \frac{-7 +- \sqrt{49 + 440 } }{2}$

$x = \frac{-7 +- \sqrt{489} }{2}$

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1 year ago

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The Frostburg-Truth bus travels on a straight road from Frostburg Mall to Sojourner Truth Park. The mall is 3 miles west and 4 m

Advocard [28]

The park is a total of 3+3 = 6 miles east of the mall, and 4+5=9 miles north of it. The Pythagorean theorem tells you the straight-line distance in miles is
√(6² +9²) = √117 ≈ 10.8

7 0

2 years ago

Find an equation for the line with the given properties. Perpendicular to the line x - 6y = 8; containing the point (4,4) O 1) y

Pepsi [2]

Answer:

Option 3 - $y=-6x+28$

Step-by-step explanation:

Given : Perpendicular to the line $x - 6y = 8$ ; containing the point (4,4).

To Find : An equation for the line with the given properties ?

Solution :

We know that,

When two lines are perpendicular then slope of one equation is negative reciprocal of another equation.

Slope of the equation $x - 6y = 8$

Converting into slope form $y=mx+c$ ,

Where m is the slope.

$y=\frac{x-8}{6}$

$y=\frac{x}{6}-\frac{8}{6}$

The slope of the equation is $m=\frac{1}{6}$

The slope of the perpendicular equation is $m_1=-\frac{1}{m}$

The required slope is $m_1=-\frac{1}{\frac{1}{6}}$

$m_1=-6$

The required equation is $y=-6x+c$

Substitute point (x,y)=(4,4)

$4=-6(4)+c$

$4=-24+c$

$c=28$

Substitute back in equation,

$y=-6x+28$

Therefore, The required equation for the line is $y=-6x+28$

So, Option 3 is correct.

8 0

2 years ago