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2 answers:
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Interpreting the inequality, it is found that the correct option is given by F.
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- The first equation is of the line.
- The equal sign is present in the inequality, which means that the line is not dashed, which removes option G.
In standard form, the equation of the line is:
Thus it is a decreasing line, which removes options J.
- We are interested in the region on the plane below the line, that is, less than the line, which removes option H.
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- As for the second equation, the normalized equation is:
- Thus, a circle centered at the origin and with radius 2.
- Now, we have to check if the line
, with coefficients
, intersects the circle, of centre
- First, we find the following distance:
- Considering the coefficients of the line and the center of the circle.
- This distance is less than the radius, thus, the line intersects the circle, which removes option K, and states that the correct option is given by F.
A similar problem is given at brainly.com/question/16505684
Answer:
The graph shifts 7 units left and 2 units up.
Step-by-step explanation:
In transformations, when a number is added or subtracted to "x" directly, that is the left/right shift.
When a number is added or subtracted outside of the "rest" of the equation, that is the up/down shift.
I learned transformations with these variables:
"a" - vertical stretch (a > 1) or compression (0 < a < 1)
"k" - horizontal stretch (0 < k < 1) or compression (k > 1)
"c" - translate left (+) or right (-)
"d" - translation up (+) or down (-)
The untranslated graph is centred around the origin f(x) = 1/x
f(x) begins 3 units right and 1 unit up of the untranslated graph.
g(x) is 4 units left and 3 units up of the untranslated graph.
y
g |
| f
-----------|------------ x
There is a 7 units translation left and 2 units translation up.