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Alina [70]
4 years ago
11

corey tracks heart rate after coming off the ice in a hockey game. in 1/6 minute, her heart beats 26 times.

Mathematics
1 answer:
Paraphin [41]4 years ago
8 0

Answer:156

Step-by-step explanation: 26÷1/6 =26×6 =156

The intensity level is moderate

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Solve 2^3x=172 Use logarithmic please
I am Lyosha [343]
2^3x = 172
3x log 2 = log 172
3x = 7.4263
x = 2.475

i am a mathematics teacher. if anything to ask please pm me
4 0
4 years ago
Pls help me i will give brainliest
soldier1979 [14.2K]

Step-by-step explanation:

13 hours

6 + 4 + 3 = 13

correct if wrong

7 0
3 years ago
Consider the function f(x)=-3x2+12x-5. What is the location of the vertex? Write your answer as an ordered pair.
natita [175]

Answer:

The (x,y) point of the vertex is usually labelled as:

Vertex = (h, k)

h = -b / 2a

k = ah^2 + bh + c

f(x) = -3x^2 + 12x -5

a = -3 b=12 c=-5

h = -12 / -6  therefore h = 2

k = -3*2^2 + 12*2 -5

k = -12 + 24 -5  therefore k = 7

Vertex (2, 7)

Source: http://www.1728.org/quadr3.htm

Step-by-step explanation:

7 0
3 years ago
A survey of athletes at a high school is conducted, and the following facts are discovered: 13% of the athletes are football pla
nekit [7.7K]

Answer:

The probability that an athlete chosen is either a football player or a basketball player is 56%.

Step-by-step explanation:

Let the athletes which are Football player be 'A'

Let the athletes which are Basket ball player be 'B'

Given:

Football players (A) = 13%

Basketball players (B) = 52%

Both football and basket ball players = 9%

We need to find probability that an athlete chosen is either a football player or a basketball player.

Solution:

The probability that athlete is a football player = P(A)= \frac{13}{100}=0.13

The probability that athlete is a basketball player = P(B)= \frac{52}{100}=0.52

The probability that athlete is both basket ball player and  football player = P(A\cap B) = \frac{9}{100}=0.09

We have to find the probability that an athlete chosen is either a football player or a basketball player P(A\cup B).

Now we know that;

P(A\cup B)= P(A) + P(B) - P(A \cap B)\\\\P(A\cup B) = 0.13+0.52-0.09=0.56\\\\P(A\cup B) = \frac{0.56}{100}=56\%

Hence The probability that an athlete chosen is either a football player or a basketball player is 56%.

5 0
4 years ago
The first lap of an auto race is 2,500 meters. This is 10% of the total race distance. What is the total race distance?
emmasim [6.3K]

Answer:

25,000

Step-by-step explanation:

.10(x) = 2,500

X = 2,500/(.10)

X=25,000

4 0
3 years ago
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