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lara31 [8.8K]
3 years ago
14

If Sterling silver is 90.0% silver and 10.0% copper, what is the maximum amount of Sterling silver that can be made if you have

48.3 grams of silver metal and an unlimited amount of copper
Chemistry
1 answer:
MArishka [77]3 years ago
8 0

Answer:

x=54g

Explanation:

From the question we are told that:

Content of Sterling silver:

Let x be sterling silver

Silver S=0.9x

Copper C=0.1x

Total  silver available T=48.3

Generally the equation for Total amount to be made is mathematically given by

T=\frac{x*90}{100}

x=\frac{48.3*100}{90}

x=54g

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Answer:

C. 7370 joules.

Explanation:

There is a mistake in the statement. Correct form is described below:

<em>Using the above data table and graph, calculate the total energy in Joules required to raise the temperature of 15 grams of ice at -5.00 °C to water at 35 °C. </em>

The total energy needed to raise the temperature is the combination of latent and sensible heats, all measured in joules, and represented by the following model:

Q = m\cdot [c_{i} \cdot (T_{2}-T_{1})+L_{f} + c_{w}\cdot (T_{3}-T_{2})] (1)

Where:

m - Mass of the sample, in grams.

c_{i} - Specific heat of ice, in joules per gram-degree Celsius.

c_{w} - Specific heat of water, in joules per gram-degree Celsius.

L_{f} - Latent heat of fusion, in joules per gram.

T_{1} - Initial temperature of the sample, in degrees Celsius.

T_{2} - Melting point of water, in degrees Celsius.

T_{3} - Final temperature of water, in degrees Celsius.

Q - Total energy, in joules.

If we know that m = 15\,g, c_{i} = 2.06\,\frac{J}{g\cdot ^{\circ}C}, c_{w} = 4.184\,\frac{J}{g\cdot ^{\circ}C}, L_{f} = 334.72\,\frac{J}{g}, T_{1} = -5\,^{\circ}C, T_{2} = 0\,^{\circ}C and T_{3} = 35\,^{\circ}C, then the final energy to raise the temperature of the sample is:

Q = (15\,g)\cdot \left[\left(2.06\,\frac{J}{g\cdot ^{\circ}C} \right)\cdot (5\,^{\circ}C)+ 334.72\,\frac{J}{g} + \left(4.184\,\frac{J}{g\cdot ^{\circ}C}\right)\cdot (35\,^{\circ}C) \right]

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When the heat lost by water = heat gained by ethanol

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Answer:

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Explanation:

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