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Hoochie [10]
2 years ago
8

Whats the área and circumference of a circle if the radius is 6in?

Mathematics
2 answers:
alina1380 [7]2 years ago
5 0

Answer:

Hello!

Area: 113.04

Circumference: 37.68

Hope this helps

Murljashka [212]2 years ago
4 0

Answer:

C≈37.7in

Step-by-step explanation:

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gladu [14]

Answer:

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3 0
2 years ago
What is the property to equation <br><br> 3+2=2+3
hoa [83]

Answer:

Commutative property w.r.t '+'

Step-by-step explanation:

3+2 =3+2

As both side contain two variable and both are adding and their answer is also same.

5=5

so this is commutative property with respect to addition.

7 0
2 years ago
What is 2 1/2 /1/3 ?
DanielleElmas [232]

Answer:

15/2

Step-by-step explanation:

My interpretation of your math expression is "2  1/2 divided by 1/3."

I prefer to write this as:

 5        1

----- ÷ -----

 2         3

which is equivalent to:

 5        3

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5 0
3 years ago
Point Q is the image of Q (-5,1) under a translation by 6 units to the right and 2 units down.
Alex787 [66]

Answer:

(1,-1)

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6 0
3 years ago
If θ=0rad at t=0s, what is the blade's angular position at t=20s
babunello [35]
The attached figure represents the relation between ω (rpm) and t (seconds)
To find the blade's angular position in radians ⇒ ω will be converted from (rpm) to (rad/s)
              ω = 250 (rpm) = 250 * (2π/60) = (25/3)π    rad/s
              ω = 100 (rpm) = 100 * (2π/60) = (10/3)π    rad/s

and from the figure it is clear that the operation is at constant speed but with variable levels
            ⇒   ω = dθ/dt   ⇒   dθ = ω dt

            ∴    θ = ∫₀²⁰  ω dt  
 
while ω is not fixed from (t = 0) to (t =20)
the integral will divided to 3 integrals as follow;
       ω = 0                                          from t = 0  to t = 5
       ω = 250 (rpm) = (25/3)π            from t = 5   to t = 15
       ω = 100 (rpm) = (10/3)π            from t = 15 to t = 20

∴ θ = ∫₀⁵  (0) dt   + ∫₅¹⁵  (25/3)π dt + ∫₁₅²⁰  (10/3)π dt
     
the first integral = 0
the second integral = (25/3)π t = (25/3)π (15-5) = (250/3)π
the third integral = (10/3)π t = (25/3)π (20-15) = (50/3)π

∴ θ = 0 + (250/3)π + (50/3)π = 100 π

while the complete revolution = 2π
so instantaneously at t = 20
∴ θ = 100 π - 50 * 2 π = 0 rad

Which mean:
the blade will be at zero position making no of revolution = (100π)/(2π) = 50
















3 0
3 years ago
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