Given : Angle < CEB is bisected by EF.
< CEF = 7x +31.
< FEB = 10x-3.
We need to find the values of x and measure of < FEB, < CEF and < CEB.
Solution: Angle < CEB is bisected into two angles < FEB and < CEF.
Therefore, < FEB = < CEF.
Substituting the values of < FEB and < CEF, we get
10x -3 = 7x +31
Adding 3 on both sides, we get
10x -3+3 = 7x +31+3.
10x = 7x + 34
Subtracting 7x from both sides, we get
10x-7x = 7x-7x +34.
3x = 34.
Dividing both sides by 3, we get
x= 11.33.
Plugging value of x=11.33 in < CEF = 7x +31.
We get
< CEF = 7(11.33) +31 = 79.33+31 = 110.33.
< FEB = < CEF = 110.33 approximately
< CEB = < FEB + < CEF = 110.33 +110.33 = 220.66 approximately
Well you solve the equation then find out what you dealing with
Answer:
5
Step-by-step explanation:
180-133=47
47-2=45
45÷9=5
Step-by-step explanation:
log 10 = 1. So if log x < 1, then x < 10. And if log x > 1, then x > 10.
The upper left number is the smallest, and can't be smaller than 1. If the exponent is 0, we can put any number in the red box.
The fractions in the upper right and lower left need to be as large as possible. The denominators will be small, and the numerators will be large.
From there, a little trial and error does the rest. The are many possible answers. I've included one.
Answer:
I think G Division Property of Equality
