Answer:
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Sorry can't answer that cause you need a diagram don't you?
Answer:
23.54 m
Step-by-step explanation:
Applying
cos∅ = adjacent(A)/hypotenuse(H)
cos∅ = A/H................ Equation 1
make H the subject of the equation
H = A/cos∅............ Equation 2
Given: A = 15 m, ∅ = 25°
Substitute into equation 2
H = 15/cos25
H = 16.55 m
Also,
tan∅ = opposite(O)/Adjacent(A)
tan∅ = O/A............Equation 3
Make O the subject of the equation
O = Atan∅.......... Equation 4
Substituting into equation 4
O = 15(tan25°)
O = 6.99 m.
From the diagram,
The height of the goal post before snap = H+O
The height of the goal post before snap = 16.55+6.99
The height of the goal post before snap = 23.54 m
a = amount (in oz) of solution A
b = amount of solution B
The scientist wants a mixture of 110 oz, so
a + b = 110
Solution A consists of 65% salt, so each ounce of solution A contributes 0.65 oz of salt; similarly, each ounce of B contributes 0.9 oz. The mixture is supposed to consist of 75% salt, which amounts to 0.75 * (110 oz) = 82.5 oz of salt. So
0.65 a + 0.9 b = 82.5
Solve for a and b:
b = 110 - a
0.65 a + 0.9 (110 - a) = 82.5
0.65 a + 99 - 0.9 a = 82.5
0.25 a = 16.5
a = 66 ==> b = 44
