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2 years ago

What is the solution to the inequality 12<8+x

1 answer:

6 0

The answer is x is greater than 4.

We simplify the answer by adding and subtracting like terms to isolate x, so I want to get rid of the 8 on the side of x so let's subtract it from that side, and what we do on one side we must do to the other side.
12 -8= 4
x+8 -8= x
So now we have 4 on the left side and x on the right side, plug the inequality back and we have our answer!

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Probability is: $\frac{\textbf{13}}{\textbf{51}}$

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From a deck of 52 cards there are 26 black cards. (Spades and Clubs).

Also, there are 26 red cards. (Hearts and Diamonds).

First, we determine the probability of drawing a black card.

P(drawing a black card) = $\frac{number \hspace{1mm} of \hspace{1mm} black \hspace{1mm} cards}{total \hspace{1mm} number \hspace{1mm} of \hspace{1mm} cards}$ $= \frac{26}{52} = \frac{\textbf{1}}{\textbf{2}}$

Now, since we don't replace the drawn card, there are only 51 cards.

But the number of red cards is still 26,

∴ P(drawing a red card) = $\frac{number \hspace{1mm} of \hspace{1mm} red \hspace{1mm} cards}{total \hspace{1mm} number \hspace{1mm}of \hspace{1mm} cards}$ $= \frac{26}{51}$

Now, the probability of both black and red card = $\frac{1}{2} \times \frac{26}{51}$

$= \frac{\textbf{13}}{\textbf{51}}$

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