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MArishka [77]
3 years ago
6

During a rainstorm a pail collects 1/3 of an inch of water in 5/6 of a minute. At what rate is the pail collecting water?

Mathematics
1 answer:
Delicious77 [7]3 years ago
4 0

Answer:

2/5 of an inch per minute

Step-by-step explanation:

You can set up the rate as  \frac{1/3}{5/6}.  From here to find the amount of rain per minute, just multiply the numerator and denominator by 6/5 (The reciprocal of 5/6, so you can have one minute and see how much rains fills up in that time.)

You end with 2/5 of and inch per minute

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How many terms in the<br> sequence are less than 100?
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Answer:

99

Step-by-step explanation:

Since given, < 100.

So,

100 - 1 = 99

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2 years ago
Solve for c:<br><br><br><br> c + (-20) = -12
alexira [117]

Answer:

8

Step-by-step explanation:

Isolate and solve for C

c + (-20) = -12\\c - 20 = -12\\c = -12+20\\c = 8

6 0
3 years ago
Read 2 more answers
Find the area of the sector.
attashe74 [19]

Answer: C . 147π / 4 mi²

Concept:

The sector is the part of a circle is enclosed by two radii of a circle and their intercepted arc.

A = (θ / 360) πr²

θ = angle of the sector

π = constant

r = radius

Solve:

<u>Given variable</u>

θ = 270°

r = 7 mi

<u>Given formula</u>

A = (θ / 360) πr²

<u>Substitute values into the formula</u>

A = (270 / 360) π (7)²

<u>Simplify exponents</u>

A = (270 / 360) π 49

<u>Simplify by multiplication</u>

A = (147 / 4) π

A = 147π / 4

Hope this helps!! :)

Please let me know if you have any questions

4 0
3 years ago
Can someone confirm this? is it correct?
EastWind [94]
<span>60 Sorry, but the value of 150 you entered is incorrect. So let's find the correct value. The first thing to do is determine how large the Jefferson High School parking lot was originally. You could do that by adding up the area of 3 regions. They would be a 75x300 ft rectangle, a 75x165 ft rectangle, and a 75x75 ft square. But I'm lazy and another way to calculate that area is take the area of the (300+75)x(165+75) ft square (the sum of the old parking lot plus the area covered by the school) and subtract 300x165 (the area of the school). So (300+75)x(165+75) - 300x165 = 375x240 - 300x165 = 90000 - 49500 = 40500 So the old parking lot covers 40500 square feet. Since we want to double the area, the area that we'll get from the expansion will also be 40500 square feet. So let's setup an equation for that: (375+x)(240+x)-90000 = 40500 The values of 375, 240, and 90000 were gotten from the length and width of the old area covered and one of the intermediate results we calculated when we figured out the area of the old parking lot. Let's expand the equation: (375+x)(240+x)-90000 = 40500 x^2 + 375x + 240x + 90000 - 90000 = 40500 x^2 + 615x = 40500 x^2 + 615x - 40500 = 0 Now we have a normal quadratic equation. Let's use the quadratic formula to find its roots. They are: -675 and 60. Obviously they didn't shrink the area by 675 feet in both dimensions, so we can toss that root out. And the value of 60 makes sense. So the old parking lot was expanded by 60 feet in both dimensions.</span>
8 0
3 years ago
Shell charges $2.23 dollars per gallon of gas for refueling vehicles. Assume the number of gallons is your independent variable
sattari [20]
Y=$2.23x
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