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stellarik [79]
2 years ago
5

Tell whether the given number is a solution of each question. ( Must show work for credit)

Mathematics
1 answer:
guajiro [1.7K]2 years ago
5 0

Answer/Step-by-step explanation:

1. 9 = 2a + 3 ; 3

Let's solve for a.

9 - 3 = 2a (subtraction property of equality)

6 = 2a

\frac{6}{2} = a (division property of equality)

3 = a

a = 3

Therefore, 3 is a solution to 9 = 2a + 3

2. 5n - (-30) = 5 ; 7

5n + 30 = 5 (- × - = +)

5n = 5 - 30 (Subtraction property of equality)

5n = -25

\frac{5n}{5} = \frac{-25}{5} (division property of equality)

n = -5

Therefore, 7 is not a solution of 5n - (-30) = 5

3. 4.4r - 2.8 = 1.6 ; 1

4.4r = 1.6 + 2.8

4.4r = 4.4

\frac{4.4r}{4.4} = \frac{4.4}{4.4}

r = 1

Therefore, 1 is a solution of 4.4r - 2.8 = 1.6.

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A librarian has 4 identical copies of Hamlet, 3 identical copies of Macbeth, 2 identical copies of Romeo and Juliet, and one cop
lesantik [10]

Answer:

The number of distinct arrangements is <em>12600</em><em>.</em>

Step-by-step explanation:

This is a permutation type of question and therefore the number of distinguishable permutations is:

n!/(n₁! n₂! n₃! ... nₓ!)

where

  • n₁, n₂, n₃ ... is the number of arrangements for each object
  • n is the number of objects
  • nₓ is the number of arrangements for the last object

In this case

  • n₁ is the identical copies of Hamlet
  • n₂ is the identical copies of Macbeth
  • n₃ is the identical copies of Romeo and Juliet
  • nₓ = n₄ is the one copy of Midsummer's Night Dream

Therefore,

<em>Number of distinct arrangements =  10!/(4! × 3! × 2! × 1!)</em>

<em>                                                         = </em><em>12600 ways</em>

<em />

Thus, the number of distinct arrangements is <em>12600</em><em>.</em>

4 0
3 years ago
9/15 + 7/15= ?<br><br><br><br><br> Pls help I’m being dumb :0
Mashutka [201]
I think the answer is 1.06666666667
7 0
3 years ago
In Janie's homeroom 54% of the students' families own a dog and 32% own a dog and a cat. What is the probability that a student'
pogonyaev

Answer:

51,111%

Step-by-step explanation:

We know that 45% have a dog but no cat.  While 23% have both a dog and a cat.

Then Pr(X has cat|X has dog) = Pr(X has dog and cat)/Pr(X has dog)

= Pr(X has dog and cat)/Pr(X has dog) = 0.23/0.45 = 0.51 ≈ 51,111%

The probability that a student’s family owns a cat if the family owns a dog is 51,111%

6 0
3 years ago
Math help its urgent. I'll mark brainliest!!!
Goshia [24]

It's been such a long time, but I think (1) should be the addition property since your adding 5 to both sides.

And (2) should be the multiplication property due to multiplying both sides by 2.
3 0
3 years ago
Type the correct answer in the box. Lily owed Megan $129.42. So far, she has paid Megan $32.56. The remaining amount Lily has ye
mario62 [17]

Answer:

$96.86

Step-by-step explanation:

129.42-32.56 = 96.86

Lily still has to pay $ 96.86

7 0
3 years ago
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