Answer:
Third quartile (Q₃) = 46.75 minutes.
Therefore, Option (c) is the correct answer.
Step-by-step explanation:
Given: Mean (μ) = 40 minutes and S.D (σ) = 10 minutes
To find : Third quartile (Q₃) = ?
Sol: As the third quartile of normal distribution covers the 75% of the total area of the curve and first quartile covers the 25% of the total area of the curve. Then with the help of z score table, the value represented the third quartile of the normal distribution is:
Q₃ = μ + 0.675 σ
Now by substitution the value of mean and standard deviation,
Q₃ = 40 + 0.675 × (10)
Q₃ = 40 + 6.75
Q₃ = 46.75
Therefore, the third quartile (Q₃) = 46.75. So, option (c) is the correct answer.
Answer:
1. 8.5 x 10^8
2. 93/10000 - 4 x 10^12
3. 9.95 x 10^12
Step-by-step explanation:
Answer:
9
Step-by-step explanation:
Slope is the same as coefficient of x
From the equation
3x+4y=12
Y=(-3/4)x+3
The slope for this eqn is -3/4
For this equation
Px+12y=30
12y=-p+30
Y= (-p/12)x +30/12
The slope is -p/12
To get p
-p/12=-3/4
P=9
3(x+7)<7(x+2)
Inequality Form: x>7/4
Interval Notation: (7/4, infinity)
<span>The probability that a house in an urban area will develop a leak is 55%. if 20 houses are randomly selected, what is the probability that none of the houses will develop a leak? round to the nearest thousandth.
Use binomial distribution, since probability of developing a leak, p=0.55 is assumed constant, and
n=20, x=0
and assuming leaks are developed independently between houses,
P(X=x)
=C(n,0)p^x* (1-p)^(n-x)
=C(20,0)0.55^0 * (0.45^20)
=1*1*0.45^20
=1.159*10^(-7)
=0.000
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