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Jet001 [13]
3 years ago
9

1/3 of a number T is less than or equal to five

Mathematics
2 answers:
ZanzabumX [31]3 years ago
8 0

Answer: x ≤ 15

Step-by-step explanation: All we need to do is divide both sides by 1/3, so1/3x / 1/3 and 5/ 1/3 = 15. So x  ≤ 15.

Hope this helps!

JulsSmile [24]3 years ago
3 0
Person above is correct
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Ddddddddddddddddddddddddddddddddddddd
zhenek [66]

Answer:

ddddddddddddddddddddddddddddddddddddd

Step-by-step explanation:

ddddddddddddddddddddddddddddddddddddd

3 0
2 years ago
Read 2 more answers
Evaluate the line integral, where c is the given curve. C xeyz ds, c is the line segment from (0, 0, 0) to (2, 3, 4)
Arada [10]

The value of line integral is, 73038 if the c is the given curve. C xeyz ds, c is the line segment from (0, 0, 0) to (2, 3, 4)

<h3>What is integration?</h3>

It is defined as the mathematical calculation by which we can sum up all the smaller parts into a unit.

The parametric equations for the line segment from (0, 0, 0) to (2, 3, 4)

x(t) = (1-t)0 + t×2 = 2t  

y(t) = (1-t)0 + t×3 = 3t

z(t) = (1-t)0 + t×4 = 4t

Finding its derivative;

x'(t) = 2

y'(t) = 3

z'(t) = 4

The line integral is given by:

\rm \int\limits_C {xe^{yz}} \, ds = \int\limits^1_0 {2te^{12t^2}} \, \sqrt{2^2+3^2+4^2} dt

 

\rm ds = \sqrt{2^2+3^2+4^2} dt

After solving the integration over the limit 0 to 1, we will get;

\rm \int\limits_C {xe^{yz}} \, ds = \dfrac{\sqrt{29}}{12}  (e^{12}-1)   or

= 73037.99 ≈ 73038

Thus, the value of line integral is, 73038 if the c is the given curve. C xeyz ds, c is the line segment from (0, 0, 0) to (2, 3, 4)

Learn more about integration here:

brainly.com/question/18125359

#SPJ4

7 0
2 years ago
let X represent the amount of time till the next student will arriv ein the library partking lot at the university. If we know t
AlekseyPX

Answer:

0.606531 = 60.6531% probability that it will take between 2 and 132 minutes for the student to arrive at the library parking lot.

Step-by-step explanation:

Exponential distribution:

The exponential probability distribution, with mean m, is described by the following equation:

f(x) = \mu e^{-\mu x}

In which \mu = \frac{1}{m} is the decay parameter.

The probability that x is lower or equal to a is given by:

P(X \leq x) = \int\limits^a_0 {f(x)} \, dx

Which has the following solution:

P(X \leq x) = 1 - e^{-\mu x}

The probability of finding a value higher than x is:

P(X > x) = 1 - P(X \leq x) = 1 - (1 - e^{-\mu x}) = e^{-\mu x}

Mean of 4 minutes

This means that m = 4, \mu = \frac{1}{4} = 0.25

Find the probability that it will take between 2 and 132 minutes for the student to arrive at the library parking lot:

This is:

P(2 \leq X \leq 132) = P(X \leq 132) - P(X \leq 2)

In which

P(X \leq 132) = 1 - e^{-0.25*132} = 1

P(X \leq 2) = 1 - e^{-0.25*2} = 0.393469

P(2 \leq X \leq 132) = P(X \leq 132) - P(X \leq 2) = 1 - 0.393469 = 0.606531

0.606531 = 60.6531% probability that it will take between 2 and 132 minutes for the student to arrive at the library parking lot.

4 0
2 years ago
Principal = $8100; rate = 17%; time = 7 years What is the amount of interest earned?
miskamm [114]
<span>it must be nnnnnnnnnnnnnnnnnnnnnnnnn
4.37%

</span>
4 0
2 years ago
Find the cost of leveling a badminton court 132m long and 58 m broad at the rate of Rs. 80 per sq. m.
serg [7]

Answer:

Rs. 612,480

Step-by-step explanation:

Hi there,

Here the question asks us to find the cost of leveling a badminton court at the rate of Rs.80 per sq..

So by the word leveling we know that we have to find the area of the court in order to proceed further.

<em>(I am assuming the court to be rectangular in shape).</em>

Area of a rectangle = Length * Breadth

*Length = 132 meters

*Breadth = 58 meters

==> 132*58= 7656 m^2

So now that we got the area of the badminton court lets find the cost of leveling it ==>

Cost of leveling per meter^2 = Rs. 80

Area = 7656 m^2

==> 7656 * 80 = 612,480

So the cost would be <u>Rs. 612,480</u>

<u></u>

<u></u>

<u><em>If you found this answer helpful please mark me as brainliest.</em></u>

8 0
2 years ago
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