Question

Two joggers start from opposite ends of an 8 mile course running towards each other. One jogger is running at a rate of 4 mph. The other is running at a rate of 6 mph. After how many minutes will the joggers meet?

Answer 1

Answer:

48 minutes

Step-by-step explanation:

Given: The distance between A and B is 8 miles. Speed of one jogger is 4 miles per hour, and speed of other jogger is 6 miles per hour.

To find: After how many minutes will the joggers meet, if they are running towards each other.

Solution:

Let both the joggers will meet after t hours, at point P between A and B.

We know that $Distance=speed\times time$

Let the jogger running at a speed of 4 miles per hour starts from point A.

So,

$AP=speed\times time$

$AP=4\times t$

$AP=4t$

Let the jogger running at a speed of 6 miles per hour starts from point B.

So,

$BP=speed\times time$

$BP=6\times t$

$BP=6t$

We have,

$AP+BP=AB$

$\implies4t+6t=8$

$\implies10t=8$

$\implies t=\frac{8}{10}$

$\implies t=0.8$

So, both the joggers will meet after 0.8 hours or $0.8\times60=48$ minutes.

Hence, the joggers will meet after 48 minutes.