Answer:
the answer is 3
Step-by-step explanation:
(-5x-3)(-5x+3)=(5x)^2 - (3)^2
A difference of squares is the difference of two squared terms.
We have
a^2 - b^2
We can factorize the difference of squared terms like this:
a^2-b^2 = (a+b)(a-b)
We have (-5x-3)(-5x+3)
Lets prove it:
(-5x-3)(-5x+3) = (-5x*-5x)+(-5x*3)+(-3*-5x)+(-3*3)
(-5x-3)(-5x+3) = 25x^2+(-15x)+(15x)+(-9)
(-5x-3)(-5x+3) = 25x^2-15x+15x-9
(-5x-3)(-5x+3) = 25x^2-9
(-5x-3)(-5x+3) = (5x)^2 - (3)^2
Answer:
0-9 = 4
10-19 = 3
20-29 = 9
30-39 = 5
Step-by-step explanation:
Answer:
12
Step-by-step explanation:
We can count the cubes.
One the right side there are 3 rows of 2 cubes each which is 6
There are 2 sets of identical " sets" of blocks
2*6 = 12
There are 12 blocks
Answer:
Step-by-step explanation:
Answer:
domain: (-5, infinity)
range: (-infinity, 2)
Step-by-step explanation: