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3 years ago

WHAT ARE THE BEST WAYS TO STUDY THE ASVAB

1 answer:

6 0

There are several study guides you can use when you’re preparing for the ASVAB. There are many ASVAB study guides available, some of which are easier to understand than others, so you’ll need to find the one that will work best for you and your learning
abilities. Here are some of the top sellers:
The ASVAB for beginners.

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30 Days to the ASVAB.

The Pass Key to the ASVAB.

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What 2 numbers multiply to be -14 and add to be -3

Svetach [21]

Xy = -14
x + y = -3

$xy = -14$
$\frac{xy}{x} = \frac{-14}{x}$
$y = \frac{-14}{x}$

$x + y = -3$
$x + \frac{-14}{x} = -3$
$\frac{x^{2}}{x} + \frac{-14}{x} = -3$
$\frac{x^{2} - 14}{x} = -3$
$x^{2} - 14 = -3x$
$x^{2} + 3x - 14 = 0$
$x = \frac{-(3) \± \sqrt{(3)^{2} - 4(1)(-14)}}{2(1)}$
$x = \frac{-3 \± \sqrt{9 + 56}}{2}$
$x = \frac{-3 \± \sqrt{65}}{2}$
$x = \frac{-3 \± 8.06}{2}$
$x = -1.5 \± 4.03$
$x = -1.5 + 4.03$ $or$ $x = -1.5 - 4.03$
$x = 2.53$ $or$ $x = -5.53$

  x + y = -3
2.53 + y = -3
- 2.53 - 2.53
  y = -5.53
  (x, y) = (2.53, -5.53)

x + y = -3
  -5.53 + y = -3
+ 5.53   + 5.53
  y = 2.53
  (x, y) = (-5.53, 2.53)

The two numbers that multiply to -14 and add up to -3 are -5.53 and 2.53.

8 0

3 years ago

Pls solve question 4b. Verrry urgent . Ok tyy

kodGreya [7K]

Answer:

$y = 3\left(x-\dfrac{3}{2}\right)^2+\dfrac{41}{4}$

Step-by-step explanation:

Given equation:

$y = 3x^2 - 9x + 17$

Factor out 3 from the first 2 terms:

$y = 3(x^2 - 3x) + 17$

Divide the coefficient of x by 2 and square it: (-3 ÷ 2)² = 9/4

Add this inside the parentheses and subtract the distributed value of it outside the parentheses:

$y = 3\left(x^2 - 3x+\dfrac{9}{4}\right) + 17-\dfrac{27}{4}$

Factor the parentheses and combine the constants:

$y = 3\left(x-\dfrac{3}{2}\right)^2+\dfrac{41}{4}$

8 0

1 year ago

Could you please help

abruzzese [7]

The answer is 9, a square has 4 equal sides so you do 36 divided by 4 and you get 9

3 0

2 years ago

Read 2 more answers

Find the dimensions of an American football field. The length is 200 ft more than the width, and the perimeter is 1,040 ft. Find

natka813 [3]

Answer:

The width of the football field is 160 feet.

The length of the football field is 360 feet.

Step-by-step explanation:

Let w represent width of the football field.

We have been given that the length is 200 ft more than the width, so the length of the field would be $w+200$ .

We are also told that the perimeter is 1,040 ft. We know that football field is in form of rectangle, so perimeter of field would be 1 times the sum of length and width. We can represent this information in an equation as:

$2(w+w+200)=1040$