Product difference would be it
First set up your two equations:
x + y = 90
x = 2y - 30
Then substitute what x equals in the second equation into the first equation:
(2y -30) + y = 90
Now solve for y:
3y -30 = 90
3y = 120
y = 40
Then use y = 40 and substitute the value for y into one of your original equations and solve for x. I'll choose the first one, but either one will work.
x+ 40 = 90
x = 50
So your solution is x = 50 and y = 40
4-5 and 3-6 are alternate interior angles
Answer is 3a²b (a + b)
Step-by-step explanation:
- Step 1: Find 3a² (ab²+b²)
⇒ 3a² (ab²+b²) = 3a³b + 3a²b² = 3a²b (a + b)