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2 years ago

3 + (−3)…………………………………………..

Mathematics

2 answers:

Leno4ka [110]2 years ago

4 0

Answer:

Step-by-step explanation:

Black_prince [1.1K]2 years ago

3 0

Answer:

Step-by-step explanation:

positive negative make negative

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If the graph of the function h is defined by = h(x)+x^2+9 is translated vertically downward by 9 units, it becomes the graph of

natulia [17]

The answer is g(x) = x².
Solution:
The graph of h(x) = x²+9 translated vertically downward by 9 units means that each point (x, h(x)) is shifted onto the point (x, h(x) - 9), that is,
(x, h(x)) → (x, h(x) - 9)
The translated graph that represents the function is defined by the expression for g(x):
g(x) = h(x) - 9 = x² + 9 - 9 = x²

h(x) = x²+9 → g(x) = x² shows that the graph of the equation g(x) = x² moves the graph of h(x) = x²+9 down nine units.

6 0

2 years ago

Write the number of measures (sides/angles/diagonals) needed to construct the following :

gladu [14]

Square :4 sides,each side 90 degrees ..

:each angle is 90 degrees

: 4 diagonals

Rectangle: 4 sides..4 angles..2 diagonals..
Rhombus : 4 sides..2 angles...2 diagonals..
Parallelogram : 4 sides..4 angles..2 diagonals..
Quadrilateral: 4 sides...4 angles...4 diagonals..

If this answer helps you plz mark as brainlist..

3 0

2 years ago

Help as soon as possible

evablogger [386]

1 and 5/16 pounds
Divide 7/8 with 2/3

4 0

2 years ago

HELP ASAP!!!!!!!!!

masha68 [24]

Answer:

Step-by-step explanation:

23550=15000(1+.0475t)

t=12

6 0

1 year ago

TO TRANSMIT INFORMATION ON THE INTERNET, LARGE FILES ARE BROKEN INTO PACKETS OF SMALLER SIZES. EACH PACKET HAS 1,500 BYTES OF IN

stich3 [128]

Answer:

A. It would be needed 20 packets to transmit 30,000 bytes of information and B. 45'000,000 (45 million) of bytes could be transmitted in 30,000 packets.

Step-by-step explanation:

1. Let's review the information provided to us for solving the question:

Size of each packet of information = 1,500 bytes

Number of packets = P

Number of bytes of information = B

2. Let's answer the questions:

A. How many packets would be needed to transmit 30,000 bytes of information?

P = 30,000 ÷ 1,500

P = 20

It would be needed 20 packets to transmit 30,000 bytes of information

B. How much information could be transmitted in 30,000 packets?

B = 30,000 * 1,500

B = 45'000,000

45'000,000 (45 million) of bytes could be transmitted in 30,000 packets.

Note: Same answer provided to question 14037480, answered by me.

7 0

2 years ago