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alexgriva [62]
3 years ago
8

Can someone pls help me with my hmwk? do as many as you can anything helps

Mathematics
1 answer:
Bogdan [553]3 years ago
7 0

Answer:

25)In order to bring this inequality to graphable form, we need to move all the terms to the left side.In my example, term -144, will be moved to the left side.

Notice that a term changes sign when it 'moves' from one side of the inequality to the other. so it will be written as 12c+144≤0 and ur answer will be

c ≤ -12

27) term 3/5, will be moved to the left side. so it will be written like this 6b+(-3/5) ≥ 3/5 + (-3/5). then it will be written as 5(6b) + (-3)/5 ≥ 3/5 - 3/5, and ur answer will be

b ≥ 1/10

29) In order to factor an integer, we need to repeatedly divide it by the ascending sequence of primes (2, 3, 5...).The number of times that each prime 'goes into' the original integer becomes its exponent in the final result.     Prime number 2 goes into 8 three times. So it will be written like this, b/8 + 2 ≤  -2 + 2, and then b/2^3 + 2 ≤ 0 and ur answer will be

b ≤ -16

31) We need to get rid of all the denominators in this inequality. This can be achieved by multiplying both the left and the right side by the Least Common Denominator. In my example, the LCD is equal to 2 x 3. So it will be written like this, 3 < 2 (-r), and then 3 < -2r and ur answer will be, rin(-\infinity ,-3/2)

Step-by-step explanation:

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Gemiola [76]

Answer:

(a) <em>H</em>₀: <em>μ ≥ 5.70 </em><em>vs. </em><em>Hₐ</em>:<em>μ < 5.70</em>

(b) The rejection region is (<em>t₀.₀₁,₉</em> <em>≤ -2.821</em>).

(c) The value of the test statistic is -4.33.

(d) The true mean breaking strength of the new bonding adhesive is less than 5.70 Mpa.

Step-by-step explanation:

A hypothesis test should be conducted to determine that the if the true mean breaking strength of the new bonding adhesive is less than 5.70 Mpa.

(a)

The hypothesis is:

<em>H</em>₀: The true mean breaking strength of the new bonding adhesive is not less than 5.70 Mpa, i.e. <em>μ ≥ 5.70</em><em>.</em>

<em>Hₐ</em>: The true mean breaking strength of the new bonding adhesive is less than 5.70 Mpa, i.e. <em>μ < 5.70</em><em>.</em>

(b)

The alternate hypothesis indicates that the hypothesis test is left-tailed.

The rejection region for the left tailed test will be towards the lower tail of the t<em>-</em>distribution curve.

The significance level of the test is: <em>α</em> = 0.01.

The critical value is:

t_{\alpha ,(n-1)}=t_{0.01,(10-1)}=t_{0.01,9}

Use the <em>t-</em>table for the critical value.

t_{\alpha ,(n-1)}=t_{0.01,9}=-2.821

Since rejection region is in the lower tail the critical value will be negative.

Thus, the rejection region is (<em>t₀.₀₁,₉</em> <em>≤ -2.821</em>).

(c)

The test statistic value is:

t=\frac{\bar x-\mu}{s/\sqrt{n}}

Given:

\bar x=5.07\\s=0.46\\n=10\\\mu=5.70

Compute the value of the <em>t</em>-statistic as follows:

t=\frac{\bar x-\mu}{s/\sqrt{n}}=\frac{5.07-5.70}{0.46/\sqrt{10}} =-4.33

The value of the test statistic is -4.33.

(d)

The value of the test is less than the critical value.

t=-4.33

This implies that the test statistic lies in the rejection region.

Hence the null hypothesis will be rejected at 1% significance level.

<u>Conclusion:</u>

As the null hypothesis is rejected it can be concluded that the true mean breaking strength of the new bonding adhesive is less than 5.70 Mpa.

(e)

The conditions required for the <em>t-</em>test for single mean to be valid is:

  • The data should be continuous.
  • The parent population should be normally distributed.
  • The sample should be randomly selected.

5 0
3 years ago
What is the slope of the line? ​
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Answer:

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Step-by-step explanation:

count the rise over run from exact pints, I used (-1,3) ans (-2,0)

3 0
3 years ago
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Answer:

see below

Step-by-step explanation:

A = pi r^2

If they have the same radius they have the same area

A two circles = pi r^2 +pi r^2

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If we double the radius

A = pi (2r)^2

   = pi 4r^2

The combined area of two circles is  1/2  the area as the area of a circle with twice the radius.

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Answer:

11(4h-3)

Step-by-step explanation:

The greatest known common factor of 44h and 33 is 11. So using the distributive property, I got 11(4h-3)

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Please answer this correctly
Nastasia [14]

Answer:

864 ft^2.

Step-by-step explanation:

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Area of the triangular sides = 4 * 1/2 * 16 * 19

Total area = 256 + 608

= 864 ft^2.

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3 years ago
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