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3 years ago

HELP ME PLEASE ‼️‼️‼️ the answers are on the picture!!!

Mathematics

1 answer:

ziro4ka [17]3 years ago

8 0

The point-slope form equation for this line is y₁ - 9 = 4 (x₁ - 1), or D.

Since these are all in point-slope form, all we need to do is find the slope and then input one value of (x, y) into the points. We start with the slope.

m = $\frac{y₁ - y}{x₁ - x}$

m = $\frac{3 - 9}{-2 -1}$

m = $\frac{-6}{-3}$

m = 2

Now we need to input the values of one of the points and slope into the point slope equation: y₁ - y = m(x₁ - x).

Inputting (1, 9), we get

y₁ - 9 = 4 (x₁ - 1)

The equation that fits it is D., so that means that the only answer to this question is D.

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the fist one

Step-by-step explanation:

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The regular price of a digital camera was 250$. Tristan bought the digital camera at a discount of 40%. How much did Tristan pay

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IgorC [24]

Answer:

Option C) $a_{n}=m-b+m(n-1)$ for $n={\{1,2,3,...}\}$ is not the correct way to define the given infinite sequence

${\{m+b,2m+b,3m+b,4m+b,...}\}$

Step-by-step explanation:

Given infinite sequence is ${\{m+b,2m+b,3m+b,4m+b,...}\}$

Option B) $a_{n}=m-b+m(n-1)$ for $n={\{1,2,3,...}\}$ is not the correct way to define the given infinite sequence ${\{m+b,2m+b,3m+b,4m+b,...}\}$

Now verify $a_{n}=m-b+m(n-1)$ for $n={\{1,2,3,...}\}$ is true for the given infinite sequence

That is put n=1,2,3,.. in the above function

$a_{n}=m-b+m(n-1)$

When n=1, $a_{1}=m-b+m(1-1)$

$=m-b+0$

$a_{1}=m-b\neq m+b$

When n=2, $a_{2}=m-b+m(2-1)$

$=m-b+m$

$a_{2}=2m-b\neq 2m+b$

When n=3, $a_{3}=m-b+m(3-1)$

$=m-b+2m$

$a_{3}=3m-b\neq 3m+b$

and so on.

Therfore $a_{n}=m-b+m(n-1)$ for $n={\{1,2,3,...}\}$ is not the correct way to define the given infinite sequence

${\{m+b,2m+b,3m+b,4m+b,...}\}$

Therefore option C) is correct

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4 years ago

Write an expression that would calculated the value of the following account after 14 years: $8100 is invested at an APR of 4.8%

Blizzard [7]

Answer:

$8100·1.024^28

Step-by-step explanation:

The future value formula is ...

FV = P(1 +r/n)^(nt)

where P is the principal invested, r is the annual interest rate, n is the number of times per year interest is compounded and t is the number of years. Putting the given numbers in place of the corresponding variables gives the expression you want:

FV = $8100(1 +.048/2)^(2·14)

FV = $8100·1.024^28 . . . . . simplified

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3 years ago