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elixir [45]
3 years ago
10

N the diagram shown, ∠7 measures 92 degrees. What is the measure of ∠8?

Mathematics
2 answers:
likoan [24]3 years ago
8 0
88 degrees.. 180-92 i think
It would be better if you could show the diagram
jeka57 [31]3 years ago
7 0
8=108 degrees because 180-92=108
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above swimming pool is leaking after 1/2 hour the pool has lead 7/8 of a gallon of water how many gallons of water per hour is a
jekas [21]
Do a proportion. X/7/8=1/1/2. 7/8 x 1= 7/8. Now do 7/8 divided by 1/2. To do this multiply 7/8 by the reciprocal of 1/2 which is 2/1. 7 x 2= 14 and 8 x 1=8. Improper fraction is 14/8. It is 1 6/8 as a mixed number which is simplified to 1 3/4. Answer is 1 3/4
7 0
2 years ago
How do I do this problem
Marina86 [1]
Rearrange the equation by subtracting what is to the right of the equal sign from both sides of the equation : 

                    <span> 5*(x-2)-4*(x+1)-(50)=0 </span>
4 0
3 years ago
Which property of real numbers is illustrated by the equation 52+(27+35= (52+27) +36?
Wittaler [7]
The answer is b associative property
6 0
2 years ago
Out of 100 students in a school, 42 take English, 35 take Chinese and 30 take French. 20 take none of the subjects, 9 take Frenc
Reptile [31]

Answer:

1 student

Step-by-step explanation:

From the Vann diagram attached below,

Let x represent the number of students who took 3 subjects.

Therefore,

100 = (42-9-11-x)+11+x+9+10+(35-10-11-x)+(30-9-10-x)+20

100 = 22-x+11+x+9+10+14-x+11-x+20

100 = 97-2x

2x = 100-97

2x = 3

x = 3/2.

x = 1.5

x = 1 student

5 0
2 years ago
It is possible to score higher than 1600 on the combined mathematics and reading portions of the SAT, but scores 1600 and above
Citrus2011 [14]

Answer:

The proportion of scores reported as 1600 is 0.0032

Step-by-step explanation:

Let X be the score for 1 random person in SAT combining maths and reading. X has distribution approximately N(μ = 1011,σ = 216).

In order to make computations, we standarize X to obtain a random variable W with distribution approximately N(0,1)

W = \frac{X-\mu}{\sigma} = \frac{X-1011}{216} \simeq N(0,1)

The values of the cummulative distribution function of the standard Normal random variable, lets denote it \phi are tabulated, you can find those values in the attached file. Now, we are ready to compute the probability of X being bigger than 1600

P(1600< X) = P(\frac{1600-1011}{216} < \frac{X-1011}{216}) = P(2.7269 < W) = 1- \phi(2.7269)\\= 1- 0.9968 = 0.0032

Hence, the proportion of scores reported as 1600 is 0.0032.

Download pdf
5 0
3 years ago
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