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k0ka [10]
4 years ago
13

Which coordinate pair satisfies both of these equations?

Mathematics
1 answer:
Vlada [557]4 years ago
7 0

Answer:

(6, -6)

Step-by-step explanation:

-4(6) - 2(-6) = -12

-24 + 12 = -12

-12 = - 12

.........................................

4(6) + 8(-6) = -24

24 - 48 = -24

-24 = -24

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Factorise <br> a) 3x^2-7x+2<br> b)2x^2-x-3<br> c)3x^2-16x-12
Luba_88 [7]

Answer: Answers are in the steps read carefully!

Step-by-step explanation:

A) 3x^2 - 7x + 2 To factor this polynomial, you have to find two numbers that their product is 6 and their sum is -7.  The numbers -1 and -6 works out because -6 times -1 is 6  and -6 plus -1 is -7.

Now rewrite the polynomial as

3x^2 - 1x - 6x + 2   Now group it  

(3x^2 - 1x) (-6x+2)  Factor it by groups

x (3x -1)  -2(3x -1)    Now factor out 3x-1  

(3x -1) (x-2)  Done!    

B)  2x^2 - x -3     Now the same way.You will have two numbers that  their product is -6 and their sum is -1. You may be wondering how I get -6 .I get -6 by multiply the leading coefficient  2 by the constant -3.  The numbers -3 and 2 works out. Because -3 times 2 is -6 and -3 plus 2 is -1.

 Rewrite the polynomial as

2x^2 +2x - 3x -3     GRoup them and factor them

(2x^2 + 2x)  (-3x-3)  

2x(x+1) -3(x+1)  Factor out x+1

(x+1) (2x -3) Done!  

C) 3x^2 - 16x - 12   Find two numbers that their product is -36 and their sum is -12. The numbers -18 and 2 works out because -18 times 2 is -36 and -18 plus 2 is -16.

Rewrite the polynomial

3x^2 +2x -18x - 12   GRoup them

 (3x^2 + 2x)   (-18x - 12)   Factor them

x (3x +2) -6(3x +2)  Factor out 3x+2

(3x+2) (x -6)  Done !

6 0
4 years ago
f(x) = x4 - 50x2 + 3 (a) Find the intervals on which f is increasing. (Enter the interval that contains smaller numbers first.)
shtirl [24]

Answer:

  (-5, 0) ∪ (5, ∞)

Step-by-step explanation:

I find a graph convenient for this purpose. (See below)

__

When you want to find where a function is increasing or decreasing, you want to look at the sign of the derivative. Here, the derivative is ...

  f'(x) = 4x^3 -100x = 4x(x^2 -25) = 4x(x +5)(x -5)

This has zeros at x=-5, x=0, and x=5. The sign of the derivative will be positive when 0 or 2 factors have negative signs. The signs change at the zeros. So, the intervals of f' having a positive sign are (-5, 0) and (5, ∞).

5 0
3 years ago
Write the equation of the line in slope-intercept form passing through the points (-4,2) and (1,12)
alexira [117]

Answer:

y = 2x + 10

Step-by-step explanation:

Find the slope:

12 - 2 / 1 - (-4)

10 / 5 = 2

Write in point-slope form:

y - 12 = 2(x - 1)

rearrange:

y - 12 = 2x - 2

y = 2x + 10

6 0
3 years ago
5x + 3y = 30<br> What is the x and y intercept
Mrac [35]
The x-intercept is + 6 and the y-intercept is + 10
4 0
4 years ago
Read 2 more answers
Which two equations would be most appropriately solved by using the zero product property?
kirza4 [7]
The first and the third equation can be solved by using the zero product property. Let us examine each equation.
4x²+16x=0
4x(x+4)=0
4x=0 and x+4=0
where x1=0 and x2=-4
Next answer is whown below:
(x+4)(x-12)=0
x1=-4 and x2=12
Therefore, the first and the third equations are the answers.
5 0
3 years ago
Read 2 more answers
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