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Gelneren [198K]
3 years ago
11

How do you solve the equation of 3(x+8)=42​

Mathematics
2 answers:
Elis [28]3 years ago
8 0

3(x+8)=42.

We move all terms to the left:

3(x+8)-(42.)=0

We add all the numbers together, and all the variables

3(x+8)-42=0

We multiply parentheses

3x+24-42=0

We add all the numbers together, and all the variables

3x-18=0

We move all terms containing x to the left, all other terms to the right

3x=18

x=18/3

x=6

Goryan [66]3 years ago
5 0
<h2>Answer: x=6</h2>

Step-by-step explanation:

Step 1: Simplify both sides of the equation.

3(x+8)=42

(3)(x)+(3)(8)=42 (Distribute)

3x+24=42

Step 2: Subtract 24 from both sides.

3x+24−24 = 42−24

3x=18

Step 3: Divide both sides by 3.

\frac{3x}{3} =\frac{18}{3}

Therefore, the correct answer is x=6

* Hopefully this helps:) Mark me the brainliest:)!!

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Answer:

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3(3x^2+13x+14)=0

3(3x+7)(x+2)=0

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Answer:

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Step-by-step explanation:

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irinina [24]

Answer:

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Step-by-step explanation:

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4 years ago
Write 56 as a product of primes.<br> Use index notation when giving your answer.
mixas84 [53]

Answer:

56 as a product of primes using index notation is: \mathbf{2^3 \times 7}

Step-by-step explanation:

We need to write 56 as a product of primes.

Prime Numbers:

<em>Numbers that are divisible by 1 or itself.</em>

Now, writing 56 as product of primes

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Now, Use index notation when giving your answer.

Index Notation:

<em>Express elements in power form i.e. if we have 2 x 2 we can write it as 2^2</em>

So, answer will be:

56 = 2 \times 2 \times 2 \times 7

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So, 56 as a product of primes using index notation is: \mathbf{2^3 \times 7}

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Step-by-step explanation:

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