End behavior is the direction the line points at both end of the graph, the end behavior for your question is : same end behavior because the leading term has the power of 6..... the line both point downwards because the leading term(-4) is negative, if the leading term is positive then the lines would point upward....if the leading term has an odd power like 3 or 5 it would be opposite end behavior
Answer:
Step-by-step explanation:
The answer: b><span><span><span>4<span> or </span></span>b</span><<span>−<span>5</span></span></span>
Answer:
Step-by-step explanation:
You might find this easier if you change h(x) to y. It might look more familiar.
you are given 1 point and that is (-1,1). What that means is when x = -1,
y = 1
You have written this as though y is linear. It is not. The power is 1/3, not 1.
Let us try B which is what I think the answer is.
y = (x + 2)^(1/3)
Put x = -1 on the right hand side.
y = (-1 + 2)^(1/3)
y = (1)^(1/3)
The cube root of 1 is 1.
So the answer is
y = (x + 2)^(1/3)
Answer:
The x-coordinate is \dfrac{\pi}{6}[/tex].
Step-by-step explanation:
We are given a function f(x) as:
Now on differentiating both side with respect to x we get that:
When 
this means that 
Hence, cosine function takes the negative value in second and third quadrant but we have to only find the value in the interval ![[0,\pi]](https://tex.z-dn.net/?f=%5B0%2C%5Cpi%5D)
.
also we know that 
----(1) (which lie in the second quadrant)
so on comparing our equation with equation (1) we obtain:
Hence, the x-coordinates where for 
is 
.
