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Vitek1552 [10]
2 years ago
7

The diameter of a volleyball is 15.5 find its radius and volume​

Mathematics
1 answer:
lilavasa [31]2 years ago
4 0

Step-by-step explanation:

diameter = 2 × radius.

15.5 = 2 × r.

r = 15.5 ÷ 2.

r = 7.75.

volume = πr²

v = π × 7.75².

v = 188.7.

I ain't confident about the volume answer but, the diameter answer is correct.

hope it helps. :)

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Step-by-step explanation:

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3 years ago
F(x)=3x-2<br>Simplify F(2x)-F(x+2)​
inysia [295]

Answer:

3x - 6

Step-by-step explanation:

To evaluate f(2x) and f(x + 2) substitute x = 2x and x = x + 2 into f(x)

f(2x) = 3(2x) - 2 = 6x - 2

f(x + 2) = 3(x + 2) - 2 = 3x + 6 - 2 = 3x + 4

Thus

f(2x) - f(x + 2)

= 6x - 2 - (3x + 4)

= 6x - 2 - 3x - 4

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7 0
3 years ago
A deck of 52 cards contains 12 picture cards. If the 52 cards are distributed in a random manner among four players in such a wa
Mkey [24]

Answer:

The probability that each player will receive three picture cards = 0.0324

Step-by-step explanation:

As given,

A deck of 52 cards contains 12 picture cards

Remaining card = 52 - 12 = 40

So,

Total number of ways in which 12 picture card is distributed = \frac{12!}{3! 3! 3! 3!}

Now,

The Total number of ways in which Remaining cards are distributed = \frac{40!}{10! 10! 10! 10!}

So,

Total number of ways of getting 3 picture card and remaining card = \frac{12!}{3! 3! 3! 3!}× \frac{40!}{10! 10! 10! 10!}

= \frac{12! 40!}{(3!)^{4} (10!)^{4}  }

Now,

Total number of ways to distribute 52 cards so that each people get 13 card = \frac{52!}{13! 13! 13! 13!} = \frac{52!}{ (13!)^{4} }

∴ The probability = \frac{\frac{12! 40!}{(3!)^{4} (10!)^{4}  }}{\frac{52!}{(13!)^{4} }}

                            = \frac{12! 40!}{(3!)^{4} (10!)^{4}  }×\frac{(13!)^{4} }{ 52! }

                           = \frac{12! 40!}{(3!)^{4} (10!)^{4}  }×\frac{(13.12.11.10!)^{4} }{ 52.51.50.49.48.47.46.45.44.43.42.41.40! }

                           = \frac{12!}{(3!)^{4}   }×\frac{(13.12.11)^{4} }{ 52.51.50.49.48.47.46.45.44.43.42.41}

                           = \frac{479,001,600}{(6)^{4}   }×\frac{(1716)^{4} }{ 52.51.50.49.48.47.46.45.44.43.42.41}

                           = 0.0324

∴ we get

The probability that each player will receive three picture cards = 0.0324

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