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lana66690 [7]
3 years ago
9

2n − 2n + 4n = 20 solve for n

Mathematics
2 answers:
olga2289 [7]3 years ago
3 0

2n-2n+4n=20

combine like terms→4n=20

divide both sides by 4→4n/4=20/4

n=5

Rashid [163]3 years ago
3 0
First we must figure out 2n-2n. This will equal 0n, or 0. Then, this means that 4n is equal to 20. As follows,

4×5=20
n=5
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Ivanshal [37]

Solution:

<u>A few definitions...</u>

  • Rational number - Any integer, fraction, terminating decimal, or repeating decimal is classified as a rational number
  • Irrational number - All the real numbers which are not rational numbers.

<u>Option A - Rational or Irrational?</u>

  • 1/2 + 1/3

Since both are known as fractions, they are rational numbers.

<u>Option B - Rational or Irrational?</u>

  • √2 + 5/2

√2 is classified as an Irrational number because if it is simplified, it does not result in any integer, fraction, terminating decimal, or repeating decimal.

<u>Option C - Rational or Irrational?</u>

  • 1/√4 + 7/2
  • => 1/2 + 7/2
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Since this is an integer, this is rational.

<u>Option D - Rational or Irrational?</u>

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8 0
2 years ago
Simplify (16+28/2-6)/10-4*2
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Answer:

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Step-by-step explanation:

4 0
3 years ago
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A population has the following characteristics.(a) A total of 25% of the population survives the first year. Of that 25%, 75% su
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Answer:

After 1st year, the age distribution will be

x_1 = \left[\begin{array}{ccc}1584\\36\\108\end{array}\right]

After 2nd year, the age distribution will be

x_2 = \left[\begin{array}{ccc}5256\\396\\27\end{array}\right]

Step-by-step explanation:

A population has the following characteristics.

A total of 25% of the population survives the first year. Of that 25%, 75% survives the second year.

The average number of offspring for each member of the population is 3 the first year, 5 the second year, and 3 the third year.

From the above information, we can construct a transition age matrix.

A = \left[\begin{array}{ccc}3&5&3\\0.25&0&0\\0&0.75&0\end{array}\right]

The population now consists of 144 members in each of the three age classes.

From the above information, we can construct the current age matrix.

x = \left[\begin{array}{ccc}144\\144\\144\end{array}\right]

How many members will there be in each age class in 1 year?

After 1st year, the age distribution will be

x_1 = A \cdot x

x_1 = \left[\begin{array}{ccc}3&5&3\\0.25&0&0\\0&0.75&0\end{array}\right] \times \left[\begin{array}{ccc}144\\144\\144\end{array}\right]

The matrix multiplication is possible since the number of columns of first matrix is equal to the number of rows of second matrix.

x_1 = \left[\begin{array}{ccc}1584\\36\\108\end{array}\right]

After 2nd year, the age distribution will be

x_2 = A \cdot x_1

x_2 = \left[\begin{array}{ccc}3&5&3\\0.25&0&0\\0&0.75&0\end{array}\right] \times \left[\begin{array}{ccc}1584\\36\\108\end{array}\right]

x_2 = \left[\begin{array}{ccc}5256\\396\\27\end{array}\right]

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<span>take 431.2 and divide by 24.5
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